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2730 questions · page 86 of 137 · choose a topic above to narrow them down
SA-9709-P3-I35-001 3 marks L2 Standard Calculator Substitution
Use the substitution u = x 2 + 4 u=x^2+4 u = x 2 + 4 to find ∫ x x 2 + 4 d x \displaystyle\int x\sqrt{x^2+4}\,dx ∫ x x 2 + 4 d x .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-002 4 marks L2 Standard Calculator Changing limits
Use the substitution u = x 2 + 1 u=x^2+1 u = x 2 + 1 to find the exact value of ∫ 0 1 x ( x 2 + 1 ) 2 d x \displaystyle\int_0^1\frac{x}{(x^2+1)^2}\,dx ∫ 0 1 ( x 2 + 1 ) 2 x d x .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-003 2 marks L2 Standard Calculator Recognising
Find ∫ cos x e sin x d x \displaystyle\int\cos x\,e^{\sin x}\,dx ∫ cos x e s i n x d x .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I36-001 3 marks L2 Standard Calculator By parts
Find ∫ x sin x d x \displaystyle\int x\sin x\,dx ∫ x sin x d x .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I36-002 3 marks L2 Standard Calculator Choosing u
Find ∫ ln x d x \displaystyle\int\ln x\,dx ∫ ln x d x , for x > 0 x>0 x > 0 .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-IN-010 4 marks L2 Standard Calculator Changing limits
Use the substitution u = x 2 + 1 u=x^2+1 u = x 2 + 1 to find ∫ 0 1 x ( x 2 + 1 ) 3 d x \displaystyle\int_0^1x(x^2+1)^3\,dx ∫ 0 1 x ( x 2 + 1 ) 3 d x .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-IN-013 3 marks L2 Standard Calculator By parts
Find ∫ x e x d x \displaystyle\int xe^x\,dx ∫ x e x d x .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE-002 3 marks L2 Standard Calculator aˣ = b
Solve 2 x + 1 = 5 x 2^{x+1}=5^x 2 x + 1 = 5 x , giving x x x correct to 3 significant figures.
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE-003 4 marks L2 Standard Calculator Disguised quadratics
Solve the equation 3 2 x − 4 ( 3 x ) + 3 = 0 3^{2x}-4\left(3^x\right)+3=0 3 2 x − 4 ( 3 x ) + 3 = 0 .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE-006 3 marks L2 Standard Calculator Combining
Solve log 2 ( x + 1 ) − log 2 x = 3 \log_2(x+1)-\log_2x=3 log 2 ( x + 1 ) − log 2 x = 3 .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE-011 4 marks L2 Standard Calculator Linear forms
Variables x x x and y y y satisfy y = k x n y=kx^n y = k x n . The graph of ln y \ln y ln y against ln x \ln x ln x is a straight line through ( 1 , 2.5 ) (1,\,2.5) ( 1 , 2.5 ) and ( 3 , 6.5 ) (3,\,6.5) ( 3 , 6.5 ) . Find n n n , and k k k correct to 3 significant figures.
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE-014 3 marks L2 Standard Calculator Graphs
The curve y = e 2 x − 3 y=e^{2x}-3 y = e 2 x − 3 crosses the x x x -axis at P P P . Find the exact x x x -coordinate of P P P and the equation of the horizontal asymptote, y = c y=c y = c .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE1-002 1 mark L2 Standard Calculator Definition
Find the value of log 9 3 \log_9 3 log 9 3 .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE2-002 2 marks L2 Standard Calculator Graphs
For y = 2 − e − x y=2-e^{-x} y = 2 − e − x , state the equation of the asymptote, y = c y=c y = c , and the y y y -intercept.
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE2-003 2 marks L2 Standard Calculator Graphs
For y = ln ( x + 3 ) y=\ln(x+3) y = ln ( x + 3 ) , state the equation of the vertical asymptote, x = a x=a x = a , and the x x x -intercept.
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE3-001 3 marks L2 Standard Calculator aˣ = b
Solve 5 2 x − 1 = 30 5^{2x-1}=30 5 2 x − 1 = 30 , giving x x x correct to 3 significant figures.
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE4-003 2 marks L2 Standard Calculator Combining
Solve ln ( 2 x + 1 ) = ln x + ln 3 \ln(2x+1)=\ln x+\ln3 ln ( 2 x + 1 ) = ln x + ln 3 .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE5-001 2 marks L2 Standard Calculator Linear forms
y = k a x y=ka^x y = k a x . The graph of ln y \ln y ln y against x x x is a straight line with intercept 0.5 0.5 0.5 and gradient 0.3 0.3 0.3 . Find k k k and a a a , each correct to 3 significant figures.
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-LE5-002 3 marks L2 Standard Calculator Finding constants
y = k x n y=kx^n y = k x n . The graph of lg y \lg y lg y against lg x \lg x lg x is a straight line through ( 1 , 3 ) (1,3) ( 1 , 3 ) and ( 3 , 7 ) (3,7) ( 3 , 7 ) . Find n n n and k k k .
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-NM-001 2 marks L2 Standard Calculator Sign change
Let f ( x ) = e x + x − 3 f(x)=e^x+x-3 f ( x ) = e x + x − 3 . Find f ( 0.5 ) f(0.5) f ( 0.5 ) and f ( 1 ) f(1) f ( 1 ) correct to 3 decimal places, and hence show that e x = 3 − x e^x=3-x e x = 3 − x has a root between 0.5 0.5 0.5 and 1 1 1 .
Salam Academy Original Practice · Proposed mark scheme