Salam Academy
Contents · 0% complete
  1. Learning objectives
  2. Core idea
  3. Key formulae
  4. Worked examples
  5. Explore the graph
  6. Common mistakes
  7. Exam tip
  8. Guided practice
  9. Practice questions
  10. Challenge
  11. Summary
  12. Quick quiz
  13. Same topic, different board
  14. Past paper questions
Statics of a particle · Subtopic 1 of 2

Resolving Forces and Equilibrium

Any force can be split into two perpendicular components: Fcos⁡θF\cos\theta along a direction and Fsin⁡θF\sin\theta across it. A particle is in equilibrium when the components in every direction add to zero, so you get two equations from two directions.

Edexcel YMA01 WME01≈ 35 minRevision 5 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Resolve a force into perpendicular components.
  • Find a resultant from several forces.
  • Solve equilibrium problems with strings and smooth slopes.
  • Use i,j\mathbf i,\mathbf j forces in equilibrium.
Pause and think

A picture hangs from two strings. Why does the tension get larger when the strings are nearly horizontal?

Section 2 of 14

Core idea

Start hereA hanging sign

A shop sign hangs from a string pushed sideways by a strut. Nothing moves, so every push is cancelled by a pull. Resolve horizontally and vertically, set each to zero, and two equations give two unknowns.

The big idea

Equilibrium: resultant force zero. Resolve in two perpendicular directions; each total is zero. Three forces in equilibrium form a closed triangle.

1. String and horizontal force

A 4 kg particle held by a string and a horizontal force
TP4g26.6°
The string makes an angle θ\theta with the vertical, where tan⁡θ=0.5\tan\theta=0.5.
Worked example4 kg on a string, tan⁡θ=0.5\tan\theta=0.5

String at θ\theta to the vertical, held by horizontal force PP. Find PP and TT.

Goal
PP, TT.
Strategy
Resolve, then divide.
  1. Tcos⁡θ=39.2T\cos\theta=39.2
    Vertical.
  2. Tsin⁡θ=PT\sin\theta=P
    Horizontal.
  3. P=39.2tan⁡θ=19.6 NP=39.2\tan\theta=19.6\text{ N}
    Divide: TT cancels.
  4. T=39.22+19.62=43.8 NT=\sqrt{39.2^2+19.6^2}=43.8\text{ N}
    Square and add.
AnswerP=19.6P=19.6 N, T=43.8T=43.8 N.
✓ CheckTT is bigger than either component ✓.
Worked exampleOn a smooth 30∘30^\circ plane

5 kg held by a force along the plane. Force and normal reaction?

Goal
FF, RR.
Strategy
Resolve along and perpendicular to the plane.
  1. F=49sin⁡30∘=24.5 NF=49\sin30^\circ=24.5\text{ N}
    Along.
  2. R=49cos⁡30∘=42.4 NR=49\cos30^\circ=42.4\text{ N}
    Perpendicular.
Answer24.524.5 N; 42.442.4 N.
✓ Check24.52+42.42=49\sqrt{24.5^2+42.4^2}=49: they balance the weight ✓.
TrickResolve perpendicular to an unknown That direction's equation won't contain it.
Pause and think

Three forces in equilibrium drawn head to tail form?

Summary

  • Resolve two ways; each sum zero.
Key words
Equilibrium
Resultant force zero.
HistoryStevin's chain. Simon Stevin, around 1586, imagined a loop of chain draped over a triangular block. Since it can't spin forever by itself, the forces along each slope must balance, which proved how forces resolve on an incline. He was so proud he put the picture on his book's title page.
Fun factTightrope walkers. A tightrope is never perfectly straight. If it were, the tension needed to support even a light walker would be infinite. Rope engineers always leave a slight sag.
Section 3 of 14

Key formulae

ComponentsFcos⁡θ (along),Fsin⁡θ (perpendicular)F\cos\theta\ \text{(along)},\qquad F\sin\theta\ \text{(perpendicular)}
Equilibrium∑Fx=0,∑Fy=0\sum F_x=0,\qquad\sum F_y=0
TrickCos for the side next to the angle. The component of a force along a line that touches the angle uses cos⁡\cos; the other uses sin⁡\sin. Mark the angle on the diagram first, then read which component is "next to" it.
Section 4 of 14

Worked examples

Example 1 · Horizontal holding force0 / 2 steps
A 33 kg particle rests on a smooth 30∘30^\circ slope, held by a horizontal force PP. Find PP.
    Example 2 · Two strings0 / 2 steps
    A 33 kg particle hangs from strings at 30∘30^\circ and 60∘60^\circ to the horizontal. Find the tensions.
      Section 5 of 14

      Explore the graph

      Components of a 10 N force
      Loading the interactive graph…
      Try this
      1. A 1010 N force at a∘a^\circ above the horizontal and its two components. The values are 10cos⁡a10\cos a and 10sin⁡a10\sin a.
      2. At what angle are the two components equal?
      3. Check that the components always satisfy x2+y2=100x^2+y^2=100.

      Horizontal component Fcos⁡θF\cos\theta, vertical component Fsin⁡θF\sin\theta.

      In the real worldSuspension bridges. Each hanger on a suspension bridge pulls on the main cable. Engineers resolve those forces at every point to find the cable's tension, which can be tens of thousands of tonnes on long bridges.
      Section 6 of 14

      Common mistakes

      IncorrectSwapping sin⁡\sin and cos⁡\cos
      CorrectCheck against the angle on the diagram
      The component next to the angle uses cos⁡\cos.
      IncorrectResolving along the slope with RR included
      CorrectRR is perpendicular to the slope
      It has no component along the slope.
      IncorrectAdding magnitudes of perpendicular forces
      CorrectPythagoras
      55 N and 1212 N at right angles give 1313 N.
      IncorrectOne equation for two unknowns
      CorrectResolve in two directions
      Two unknowns need two equations.
      1. Guess the forces balance

      2. Resolve in two directions

      3. Lami's theorem or a triangle of forces when there are exactly three

      Section 7 of 14

      Exam tip

      Exam tipState the directions. Write "Resolving vertically:" and "Resolving parallel to the plane:" before each equation. Examiners award method marks per direction, and labelled equations make them easy to give.
      Section 8 of 14

      Guided practice

      SA-IAL-M1-ST-G011 markL1 FoundationCalculatorEquilibrium
      A particle of mass 22 kg hangs at rest on a vertical string. Find the tension.

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      Salam Academy Original Practice · Proposed mark scheme
      Section 9 of 14

      Practice questions

      SA-IAL-M1-ST-0012 marksL1 FoundationCalculatorResolving
      Forces of 55 N due east and 1212 N due north act on a particle. Find the magnitude of the resultant.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST1-0021 markL1 FoundationCalculatorResolving
      A force of 1010 N acts at 30∘30^\circ above the horizontal. Find its horizontal component, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST-0022 marksL1 FoundationCalculatorEquilibrium
      A particle of mass 33 kg is held at rest on a smooth plane inclined at 30∘30^\circ by a force PP acting up the line of greatest slope. Find PP.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST1-0032 marksL1 FoundationCalculatorEquilibrium
      A 44 kg particle is held at rest on a smooth plane inclined at 25∘25^\circ by a force acting up the line of greatest slope. Find the force, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST-0033 marksL2 StandardCalculatorEquilibrium
      A particle of mass 33 kg is held at rest on a smooth plane inclined at 30∘30^\circ by a horizontal force PP. Find PP, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST1-0012 marksL2 StandardNon-calculatorEquilibrium
      Forces (pi+2j)(p\mathbf i+2\mathbf j) N, (−3i+qj)(-3\mathbf i+q\mathbf j) N and (i−5j)(\mathbf i-5\mathbf j) N act on a particle in equilibrium. Find pp and qq.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST-0083 marksL2 StandardCalculatorEquilibrium
      Three forces F1=(3i+4j)\mathbf F_1=(3\mathbf i+4\mathbf j) N, F2=(−5i+j)\mathbf F_2=(-5\mathbf i+\mathbf j) N and F3\mathbf F_3 act on a particle in equilibrium. Find the magnitude of F3\mathbf F_3, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST1-0042 marksL2 StandardCalculatorResolving
      A particle of weight 1010 N hangs from two strings at right angles to each other. One string makes 30∘30^\circ with the vertical. Find the tension in that string, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-IAL-M1-ST-0096 marksL3 ExamCalculatorEquilibrium
      A particle of mass 33 kg hangs in equilibrium from two light strings. One string makes an angle of 30∘30^\circ with the horizontal and the other makes an angle of 60∘60^\circ with the horizontal, on the other side. Find the tension in each string. (g=9.8g=9.8)

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      Salam Academy Original Practice · Proposed mark scheme

      More questions on every skill in this subtopic are in the question bank under Practise.

      Section 10 of 14

      Challenge

      SA-IAL-M1-ST-0066 marksL3 ExamCalculatorEquilibrium
      A particle of mass 55 kg hangs in equilibrium from two light strings inclined at 30∘30^\circ and 60∘60^\circ to the horizontal. Find the tensions T1T_1 (the 30∘30^\circ string) and T2T_2 (the 60∘60^\circ string), to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      Section 11 of 14

      Summary

      • Components: Fcos⁡θF\cos\theta along, Fsin⁡θF\sin\theta across.
      • Equilibrium: components sum to zero in every direction.
      • Resolve in two directions for two unknowns.
      • Choose directions to avoid unknowns.
      Section 12 of 14

      Quick quiz

      Q1 · SA-IAL-M1-ST-Q021 markL1 FoundationCalculatorEquilibrium
      A particle is in equilibrium. Which must be true?
      Choose one option

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      Salam Academy Original Practice · Proposed mark scheme
      Section 13 of 14

      Same topic, different board

      Specification
      IAL Mathematics, unit WME01 (Mechanics 1)
      Where
      M1 · 5 Statics of a particle
      Expected
      Resolve forces in two perpendicular directions; a particle is in equilibrium when the resultant is zero; problems with strings, smooth slopes and forces given in i, j form.
      Calculator
      Calculators are permitted, but exact answers (surds, fractions, π) are expected where the question asks.
      Typical style
      "A particle hangs in equilibrium from two strings… find the tension in each string."
      Open in
      YMA01 · WME01
      Section 14 of 14

      Past paper questions

      1 question (12 marks) from real exams test this subtopic. Try each one under timed conditions, then mark it with the official mark scheme.

      1. WME01/01 · January 2025Question 612 marks

        Particle on a rough slope in limiting equilibrium, and whether it stays at rest when the string breaks.

      All YMA01 past paper questions by topic

      Salam Academy original content · Content status: reviewed and published. Syllabus mapping: Pearson Edexcel YMA01, 2018 specification (official specification).