Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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2730 questions · page 31 of 137 · choose a topic above to narrow them down

SA-9709-P2-AL-G012 marksL1 FoundationCalculatorEquations
Solve the equation ∣3x−2∣=7|3x-2|=7.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P2-DF-0143 marksL1 FoundationCalculatorParametric
A curve has parametric equations x=t2x=t^2, y=2ty=2t. Find the gradient of the curve at the point where t=2t=2.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P2-DF-G012 marksL1 FoundationCalculatorStandard derivatives
Differentiate y=e3x+ln⁡(2x)y=e^{3x}+\ln(2x) with respect to xx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P2-IN-0012 marksL1 FoundationCalculatorStandard integrals
Find ∫12x+3 dx\displaystyle\int\frac{1}{2x+3}\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P2-IN-0033 marksL1 FoundationCalculatorExact integrals
Find the exact value of ∫01e2x dx\displaystyle\int_0^1e^{2x}\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P2-IN-G012 marksL1 FoundationCalculatorStandard integrals
Find ∫(e4x+3x)dx\displaystyle\int\left(e^{4x}+\frac3x\right)dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL-0022 marksL1 FoundationCalculatorSimple
The solution of ∣x−3∣<2|x-3|<2 is a<x<ba<x<b. Find aa and bb.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL-0042 marksL1 FoundationCalculatorRemainder theorem
Find the remainder when x3−4x2+2x+5x^3-4x^2+2x+5 is divided by (x−3)(x-3).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL-0083 marksL1 FoundationCalculatorLinear factors
Express 5x+1(x−1)(x+2)\dfrac{5x+1}{(x-1)(x+2)} in the form Ax−1+Bx+2\dfrac{A}{x-1}+\dfrac{B}{x+2}.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL1-0012 marksL1 FoundationCalculatorGraphs
For the graph of y=∣2x+4∣y=|2x+4|, state the xx-coordinate of the vertex and the yy-intercept.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL2-G012 marksL1 FoundationCalculatorSimple
The solution of ∣x−1∣<3|x-1|<3 is a<x<ba<x<b. Find aa and bb.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL4-G012 marksL1 FoundationCalculatorLinear factors
Express 3(x+1)(x−2)\dfrac{3}{(x+1)(x-2)} in the form Ax+1+Bx−2\dfrac{A}{x+1}+\dfrac{B}{x-2}.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL5-G013 marksL1 FoundationCalculatorExpanding
Expand (1+x)−1(1+x)^{-1} in ascending powers of xx, up to and including the term in x3x^3.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-AL-G012 marksL1 FoundationCalculatorEquations
Solve the equation ∣2x−3∣=5|2x-3|=5.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-CX-0012 marksL1 FoundationCalculatorArithmetic
Express (2−3i)2(2-3i)^2 in the form x+iyx+iy.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-CX-0043 marksL1 FoundationCalculatorPolynomial roots
Solve the equation z2−4z+13=0z^2-4z+13=0.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-CX-0142 marksL1 FoundationCalculatorPolar form
Express z=2(cos⁡π6+isin⁡π6)z=2\left(\cos\dfrac\pi6+i\sin\dfrac\pi6\right) in the form x+iyx+iy, giving exact values.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-CX1-0011 markL1 FoundationCalculatorArithmetic
Express (4+3i)+(2−5i)−(1−i)(4+3i)+(2-5i)-(1-i) in the form x+iyx+iy.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-CX1-0022 marksL1 FoundationCalculatorArithmetic
Express (3+2i)(4−i)(3+2i)(4-i) in the form x+iyx+iy.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-CX2-0011 markL1 FoundationCalculatorModulus–argument
Find ∣5−12i∣|5-12i|.

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Salam Academy Original Practice · Proposed mark scheme