Salam Academy
Contents · 0% complete
  1. Learning objectives
  2. Core idea
  3. Key formulae
  4. Worked examples
  5. Explore the graph
  6. Common mistakes
  7. Exam tip
  8. Guided practice
  9. Practice questions
  10. Challenge
  11. Summary
  12. Quick quiz
  13. Same topic, different board
  14. Past paper questions
Groups · Subtopic 1 of 1

Groups

A group is a set with an operation that is closed and associative, has an identity, and gives every element an inverse. The order of an element is the smallest power giving the identity. By Lagrange's theorem, the order of any subgroup divides the order of the group.

Edexcel 9FM0 OptionAQA 7367 Paper 3≈ 50 minRevision 1 · updated 2026-10-27
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Section 1 of 14

Learning objectives

  • Check the four group axioms for a set and binary operation.
  • Construct and read Cayley tables.
  • Find orders of elements; recognise cyclic groups and generators.
  • Use Lagrange's theorem to find possible subgroups; identify isomorphic groups.
Pause and think

Rotations of a square by 0∘,90∘,180∘,270∘0^\circ,90^\circ,180^\circ,270^\circ: combining two always gives another. Can every rotation be undone by one of them?

Section 2 of 14

Core idea

Start hereSymmetries you can combine

Turn a square through 90∘90^\circ, then 180∘180^\circ: you've turned it 270∘270^\circ. Any two rotations combine into another, there's a "do nothing" rotation, and every rotation can be undone. Those few facts, and nothing else, are what make something a group.

The big idea

A group (G,∗)(G,*) is a set with an operation that is closed, associative, has an identity ee, and gives every element an inverse. From those four axioms follow orders of elements, cyclic groups, subgroups and Lagrange's theorem.

1. The four axioms

a∗b∈G; (a∗b)∗c=a∗(b∗c); a∗e=e∗a=a; a∗a−1=a−1∗a=ea*b\in G;\ (a*b)*c=a*(b*c);\ a*e=e*a=a;\ a*a^{-1}=a^{-1}*a=e
where
ee
identity element.
a−1a^{-1}
inverse of aa.
Worked exampleA non-standard operation

On Z\mathbb Z, a∗b=a+b−2a*b=a+b-2. Show there is an identity and find the inverse of 55.

Goal
ee and 5−15^{-1}.
Strategy
Solve a∗e=aa*e=a, then 5∗x=e5*x=e.
  1. a+e−2=a⇒e=2a+e-2=a\Rightarrow e=2
    Definition of identity.
  2. 5+x−2=25+x-2=2
    Inverse combines to e=2e=2.
  3. x=−1x=-1
    Solve.
Answere=2e=2, 5−1=−15^{-1}=-1.
✓ Check5∗(−1)=5−1−2=25*(-1)=5-1-2=2 ✓.

2. Orders and cyclic groups

Powers of 33 under ×7\times_7
  1. 31=3, 32=9≡23^1=3,\ 3^2=9\equiv2
    Reduce mod 77 each time.
  2. 33≡6, 34≡18≡43^3\equiv6,\ 3^4\equiv18\equiv4
    Multiply the previous result by 33.
  3. 35≡12≡5, 36≡15≡13^5\equiv12\equiv5,\ 3^6\equiv15\equiv1
    Back to the identity.
Order 66: the powers list every element, so 33 is a generator and the group is cyclic.
Why Lagrange's theorem holds (sketch)
  1. gH={gh:h∈H}gH=\{gh:h\in H\}
    Form cosets of the subgroup HH.
  2. ∣gH∣=∣H∣|gH|=|H|
    h↦ghh\mapsto gh is one-to-one (cancel gg).
  3. cosets are equal or disjoint\text{cosets are equal or disjoint}
    If they share an element they share all.
  4. ∣G∣=k∣H∣|G|=k|H|
    GG splits into kk equal pieces.
So ∣H∣|H| divides ∣G∣|G|, and the order of each element divides ∣G∣|G|.
Worked examplePossible subgroups

A group has order 1515. What orders can its subgroups have?

Goal
A list.
Strategy
Lagrange.
  1. ∣H∣∣15|H|\mid15
    Lagrange.
  2. 1,3,5,151,3,5,15
    Divisors of 1515.
Answer1,3,5,151,3,5,15; proper non-trivial subgroups have order 33 or 55.
✓ CheckLagrange says which orders are possible, not that each one exists; for order 1515 they do.
Testing for a group

Fail any one test and it is not a group.

Key takeawayIsomorphism Two groups are isomorphic if a one-to-one matching preserves the operation. Quick checks: same order, same number of elements of each order.
Common misconceptionZero under multiplication {0,1,2,3}\{0,1,2,3\} under ×4\times_4 is not a group: 00 and 22 have no inverses.
Pause and think

Can a group of order 7 have a subgroup of order 2?

Summary

  • Closure, associativity, identity, inverses.
  • Order of aa: least nn with an=ea^n=e.
  • Cyclic: generated by one element.
  • Lagrange: ∣H∣|H| divides ∣G∣|G|.
Key words
Abelian
Group with ab=baab=ba for all elements.
Cayley table
Grid of all products in a group.
Subgroup
Subset that is a group under the same operation.
HistoryÉvariste Galois. Galois invented group theory to show which polynomial equations can be solved by radicals. He wrote it up the night before a fatal duel in 1832, aged 20.
Fun factRubik's cube. The moves of a Rubik's cube form a group with 43 252 003 274 489 856 00043\,252\,003\,274\,489\,856\,000 elements, and every position can be solved in 20 moves or fewer.
Section 3 of 14

Key formulae

Axiomsclosure, (ab)c=a(bc), ∃e:ae=ea=a, ∀a ∃a−1:aa−1=e\text{closure},\ (ab)c=a(bc),\ \exists e: ae=ea=a,\ \forall a\ \exists a^{-1}: aa^{-1}=e
Order of an elementord⁡(a)=min⁡{n≥1:an=e}\operatorname{ord}(a)=\min\{n\ge1: a^n=e\}
Lagrange's theorem∣H∣ divides ∣G∣ for every subgroup H|H|\ \text{divides}\ |G|\ \text{for every subgroup }H
TrickLatin squares. In a group's Cayley table every element appears exactly once in each row and column. If not, it isn't a group.
Section 4 of 14

Worked examples

Example 1 · Multiplication mod 70 / 3 steps
Find the order of 33 in {1,2,3,4,5,6}\{1,2,3,4,5,6\} under ×7\times_7.
    Example 2 · A strange operation0 / 2 steps
    On Z\mathbb Z, a∗b=a+b−2a*b=a+b-2. Find the identity and the inverse of 55.
      Section 5 of 14

      Explore the graph

      Powers of a rotation
      Loading the interactive graph…
      Try this
      1. Rotation by 2πn\frac{2\pi}n has order nn: after nn steps you're back at the start.
      2. This cyclic group of order nn is isomorphic to integers under +n+_n.

      The cyclic group CnC_n as rotations.

      In the real worldCryptography. Online banking uses groups of points on elliptic curves; security rests on how hard it is to undo repeated group operations.
      Section 6 of 14

      Common mistakes

      IncorrectAssuming commutativity
      CorrectNot required
      Groups need not be abelian (e.g. matrix multiplication).
      IncorrectForgetting closure
      CorrectCheck results stay in the set
      E.g. odd numbers under ++ fail closure.
      IncorrectOrder of element == the element
      CorrectSmallest nn with an=ea^n=e
      In (Z10,+)(\mathbb Z_{10},+), 22 has order 55.

      Me: is it a group?

      Closure, identity, inverses, associativity. No vibes allowed.

      Section 7 of 14

      Exam tip

      Exam tipAssociativity from known structures. You can usually quote associativity: addition, multiplication, matrix multiplication and composition of functions are all associative.
      Section 8 of 14

      Guided practice

      SA-FP-GR-G012 marksL2 StandardNon-calculatorOrders
      Find the order of 33 in the group {1,2,3,4,5,6}\{1,2,3,4,5,6\} under multiplication mod 77.

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      Salam Academy Original Practice · Proposed mark scheme
      Section 9 of 14

      Practice questions

      SA-FP-GR-0011 markL1 FoundationNon-calculatorAxioms
      In {1,3,5,7}\{1,3,5,7\} under multiplication mod 88, find the inverse of 55.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-FP-GR-0021 markL2 StandardNon-calculatorOrders
      Find the order of 22 in (Z10,+10)(\mathbb Z_{10},+_{10}).

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      Salam Academy Original Practice · Proposed mark scheme
      SA-FP-GR-0032 marksL2 StandardNon-calculatorSubgroups
      A group has order 1212. How many different orders are possible for its subgroups (including trivial and whole group)?

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      Salam Academy Original Practice · Proposed mark scheme
      SA-FP-GR-0042 marksL2 StandardNon-calculatorOrders
      How many generators does the cyclic group (Z8,+8)(\mathbb Z_8,+_8) have?

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      Salam Academy Original Practice · Proposed mark scheme

      More questions on every skill in this subtopic are in the question bank under Practise.

      Section 10 of 14

      Challenge

      SA-FP-GR-0053 marksL3 ExamNon-calculatorAxioms
      On Z\mathbb Z, define a∗b=a+b−2a*b=a+b-2. Find the inverse of 55.

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      Salam Academy Original Practice · Proposed mark scheme
      Section 11 of 14

      Summary

      • Four axioms.
      • Order of element: first power giving ee.
      • Cyclic: one element generates all.
      • Lagrange: subgroup orders divide ∣G∣|G|.
      Section 12 of 14

      Quick quiz

      Q1 · SA-FP-GR-Q011 markL1 FoundationNon-calculatorAxioms
      Which is NOT one of the group axioms?
      Choose one option

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      Salam Academy Original Practice · Proposed mark scheme
      Section 13 of 14

      Same topic, different board

      Specification
      A level Further Mathematics 9FM0
      Where
      Further Pure 2 · Groups
      Expected
      Group axioms, Cayley tables, orders of elements and groups, cyclic groups, subgroups, Lagrange's theorem, isomorphism.
      Calculator
      Permitted; show enough working to earn the method marks.
      Typical style
      Edexcel often opens with a routine part and builds to a "show that" or "prove" part.
      Open in
      9FM0 · Option
      Section 14 of 14

      Past paper questions

      No past paper questions are tagged to this subtopic yet. We add papers every week.

      Browse past papers

      Salam Academy original content · Content status: reviewed and published. Syllabus mapping: Pearson Edexcel 9FM0, First teaching 2017 (official specification).