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Contents · 0% complete
  1. Learning objectives
  2. Core idea
  3. Key formulae
  4. Worked examples
  5. Explore the graph
  6. Common mistakes
  7. Exam tip
  8. Guided practice
  9. Practice questions
  10. Challenge
  11. Summary
  12. Quick quiz
  13. Same topic, different board
  14. Past paper questions
Geometry and trigonometry · Subtopic 10 of 11

Pythagoras' Theorem

In a right-angled triangle, the square on the hypotenuse equals the sum of the squares on the other two sides: a2+b2=c2a^2+b^2=c^2. Add the squares to find the hypotenuse; subtract to find a shorter side.

Cambridge 4024 Paper 1Cambridge 4024 Paper 2Edexcel 4MA1 Papers 1H, 2HEdexcel 4MA1 Papers 1F, 2FAQA 8300 Papers 1–3≈ 25 minRevision 5 · updated 2026-10-27
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Section 1 of 14

Learning objectives

  • Identify the hypotenuse as the side opposite the right angle.
  • Find the hypotenuse, or a shorter side, of a right-angled triangle.
  • Use Pythagoras in practical problems and to find the distance between two points.
  • Test whether a triangle is right-angled.
Pause and think

Draw squares on each side of a 33-44-55 triangle. What are their areas, and what do you notice?

Section 2 of 14

Core idea

Start hereWill the ladder reach?

A 5 m ladder leans against a wall with its foot 1.5 m out. How high does it reach? The wall, ground and ladder make a right-angled triangle, and Pythagoras links its three sides.

The big idea

Right-angled triangle: a2+b2=c2a^2+b^2=c^2, cc the hypotenuse (opposite the right angle).

1. The theorem

Squares on the sides of a 3-4-5 triangle
16925
9+16=259+16=25. The two smaller squares together have exactly the same area as the big one.
A proof by rearrangement
  1. big square side a+b\text{big square side }a+b
    Place four copies of the triangle inside.
  2. (a+b)2=4⋅12ab+c2(a+b)^2=4\cdot\tfrac12ab+c^2
    Four triangles + tilted inner square of side cc.
  3. a2+2ab+b2=2ab+c2a^2+2ab+b^2=2ab+c^2
    Expand.
  4. a2+b2=c2a^2+b^2=c^2
    Cancel 2ab2ab.
Worked exampleHypotenuse

Sides 5 and 12.

Goal
cc.
Strategy
Square, add, root.
  1. 25+144=16925+144=169
    Add squares.
  2. c=13c=13
    Root.
Answer1313.
✓ CheckLongest side ✓.
Worked exampleThe ladder

5 m ladder, foot 1.5 m out.

Goal
Height.
Strategy
Square, subtract, root.
  1. h2=25−2.25=22.75h^2=25-2.25=22.75
    Hypotenuse is the ladder.
  2. h=4.77 mh=4.77\text{ m}
    Root.
Answer4.774.77 m.
✓ CheckLess than 5 ✓.
Worked exampleIs it right-angled?

Sides 7, 24, 25 and 6, 8, 11.

Goal
Yes/no.
Strategy
Converse: check a2+b2=c2a^2+b^2=c^2.
  1. 49+576=625=25249+576=625=25^2
    Yes.
  2. 36+64=100≠12136+64=100\neq121
    No (obtuse, since 121>100121>100).
AnswerFirst yes; second no.
✓ CheckLargest side always as cc ✓.
Common misconceptionAdding for a shorter side If the hypotenuse is known, subtract.
Pause and think

Distance between (1,2)(1,2) and (7,10)(7,10)?

Summary

  • Square, add, root for hypotenuse.
  • Square, subtract, root for a shorter side.
Key words
Hypotenuse
Longest side, opposite the right angle.
HistoryOlder than Pythagoras. Pythagoras lived around 500500 BC, but a Babylonian clay tablet known as Plimpton 322, written about 18001800 BC, already lists sets of numbers that fit a2+b2=c2a^2+b^2=c^2. The theorem was also known in ancient India and China. Pythagoras' followers may have been the first to prove it in general.
Fun factBuilders' 3-4-5 trick. To mark a perfect right angle without a protractor, builders measure 33 m along one wall, 44 m along the other, and adjust until the diagonal is exactly 55 m. It works because 32+42=523^2+4^2=5^2.
Section 3 of 14

Key formulae

Pythagoras' theorema2+b2=c2a^2+b^2=c^2
Distance between two pointsd=(x2−x1)2+(y2−y1)2d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
TrickKnow the triples. 3,4,53,4,5; 5,12,135,12,13; 8,15,178,15,17; 7,24,257,24,25 and their multiples (6,8,106,8,10; 9,12,159,12,15) come up again and again. Spot one and you can write the answer down without a calculator.
Section 4 of 14

Worked examples

Example 1 · Ladder0 / 2 steps
A 55 m ladder leans against a vertical wall with its foot 1.51.5 m from the wall. How high up the wall does it reach?
    Example 2 · Isosceles triangle0 / 2 steps
    An isosceles triangle has equal sides of 1010 cm and a base of 1212 cm. Find its height.
      Section 5 of 14

      Explore the graph

      A right-angled triangle
      Loading the interactive graph…
      Try this
      1. The value below the sliders is the hypotenuse a2+b2\sqrt{a^2+b^2}.
      2. Find all the whole-number pairs a,ba,b up to 1212 that give a whole-number hypotenuse.
      3. Double both aa and bb. What happens to the hypotenuse?

      Whole-number solutions to a2+b2=c2a^2+b^2=c^2 are called Pythagorean triples.

      In the real worldScreen sizes are hypotenuses. A "5555-inch" TV is 5555 inches along the diagonal. With a 16:916:9 screen, Pythagoras gives a width of about 4848 inches and a height of about 2727 inches.
      Section 6 of 14

      Common mistakes

      IncorrectAdding when finding a shorter side
      CorrectSubtract
      a2=c2−b2a^2=c^2-b^2.
      Incorrect92+122=9+12\sqrt{9^2+12^2}=9+12
      Correct225=15\sqrt{225}=15
      Square roots do not split over addition.
      IncorrectTreating any side as cc
      Correctcc is opposite the right angle
      It must be the longest side.
      IncorrectForgetting the square root
      Correctc2=225⇒c=15c^2=225\Rightarrow c=15
      225225 is c2c^2, not cc.

      Adding the two longest sides

      a2+b2=c2a^2+b^2=c^2, where cc is opposite the right angle

      Section 7 of 14

      Exam tip

      Exam tipLabel first. Mark the hypotenuse with a cc before you write anything. Then decide: finding cc? add. Finding another side? subtract. Write the line c2=a2+b2c^2=a^2+b^2 with numbers in it to secure the method mark.
      Section 8 of 14

      Guided practice

      SA-4024-TR-G012 marksL1 FoundationNon-calculatorHypotenuse
      A right-angled triangle has shorter sides 99 cm and 1212 cm. Find the length of the hypotenuse.

      Sign in or create a free account to check answers, get hints and track your progress.

      Salam Academy Original Practice · Proposed mark scheme
      Section 9 of 14

      Practice questions

      SA-4024-TR1-0012 marksL1 FoundationNon-calculatorHypotenuse
      A right-angled triangle has shorter sides 66 cm and 88 cm. Find the hypotenuse.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0022 marksL1 FoundationNon-calculatorHypotenuse
      A right-angled triangle has shorter sides 77 cm and 2424 cm. Find the hypotenuse.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0042 marksL1 FoundationCalculatorHypotenuse
      A right-angled triangle has shorter sides 55 cm and 99 cm. Find the hypotenuse, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR-0012 marksL1 FoundationNon-calculatorPythagoras problems
      A right-angled triangle has hypotenuse 1313 cm and one other side 55 cm. Find the third side.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0032 marksL1 FoundationNon-calculatorPythagoras problems
      A right-angled triangle has hypotenuse 1717 cm and one shorter side 88 cm. Find the third side.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0062 marksL1 FoundationNon-calculatorHypotenuse
      Find the length of the diagonal of a rectangle 1212 cm by 55 cm.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0052 marksL2 StandardCalculatorPythagoras problems
      A 55 m ladder leans against a vertical wall. Its foot is 1.51.5 m from the wall on level ground. How high up the wall does it reach? Give your answer to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0072 marksL2 StandardNon-calculatorPythagoras problems
      Find the distance between the points (1,2)(1,2) and (7,10)(7,10).

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      Salam Academy Original Practice · Proposed mark scheme
      SA-4024-TR1-0093 marksL2 StandardNon-calculatorPythagoras problems
      An isosceles triangle has two sides of 1010 cm and a base of 1212 cm. Find its perpendicular height.

      Sign in or create a free account to check answers, get hints and track your progress.

      Salam Academy Original Practice · Proposed mark scheme

      More questions on every skill in this subtopic are in the question bank under Practise.

      Section 10 of 14

      Challenge

      SA-4024-TR-0113 marksL3 ExamCalculatorPythagoras problems
      A ship sails 1212 km on a bearing of 060∘060^\circ, then 88 km on a bearing of 150∘150^\circ. Find its distance from the starting point, to 3 significant figures.

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      Salam Academy Original Practice · Proposed mark scheme
      Section 11 of 14

      Summary

      • a2+b2=c2a^2+b^2=c^2, with cc the hypotenuse.
      • Hypotenuse: add the squares. Shorter side: subtract.
      • Distance between points: Pythagoras on the xx and yy differences.
      • If a2+b2≠c2a^2+b^2\ne c^2, the triangle is not right-angled.
      Section 12 of 14

      Quick quiz

      Q1 · SA-4024-TR1-0081 markL2 StandardCalculatorPythagoras problems
      Is a triangle with sides 99 cm, 1212 cm and 1616 cm right-angled?
      Choose one option

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      Salam Academy Original Practice · Proposed mark scheme
      Section 13 of 14

      Same topic, different board

      Specification
      International GCSE Mathematics A 4MA1
      Where
      Geometry and trigonometry
      Expected
      The same, including the distance between two points.
      Calculator
      Calculator allowed in both papers.
      Typical style
      Similar question styles; some content is Higher tier only.
      Open in
      4MA1 · Papers 1H, 2H4MA1 · Papers 1F, 2F
      Section 14 of 14

      Past paper questions

      1 question (4 marks) from real exams test this subtopic. Try each one under timed conditions, then mark it with the official mark scheme.

      1. 4024/12 · Oct/Nov 2025Question 234 marks

        Pythagoras in a square-based pyramid, giving a surd.

      All 4024 past paper questions by topic

      Salam Academy original content · Content status: reviewed and published. Syllabus mapping: Pearson Edexcel 4MA1, 2016 specification (official specification).