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Motion of a projectile · Subtopic 1 of 1

Projectile Motion

A projectile moves horizontally at constant velocity while accelerating vertically at gg. The two motions are independent and share only the time of flight. Resolve the launch velocity into components, solve the vertical motion for the time, then use it for the horizontal distance. Air resistance shortens the range and makes the path lopsided.

Cambridge 9231 Paper 3Cambridge 9702 Paper 1Cambridge 9702 Paper 2Edexcel YPH11 WPH11AQA 7408 Paper 1≈ 40 minRevision 6 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Explain why horizontal and vertical motion are independent.
  • Solve problems for horizontally launched projectiles.
  • Solve problems for projectiles launched at an angle: time of flight, range and maximum height.
  • Describe the effect of air resistance on a trajectory.
Pause and think

At the same moment, one bullet is fired horizontally from a gun and another is dropped from the same height. Ignoring air resistance, which hits the ground first?

Section 2 of 14

Core idea

Start hereDropped and fired bullets land together

Fire a bullet horizontally and drop another from the same height at the same instant: on flat ground, they hit at the same time. Horizontal motion doesn't affect vertical motion. That independence is the whole key to projectiles.

The big idea

Split motion: horizontal constant velocity; vertical acceleration gg down. Time links the two.

1. Independence

Projectile launched at 20 m/s and angle θ
1020304051015200horizontal distance (m)height (m)pathu
Range is greatest at 45∘45^\circ (about 40.8 m). Angles that add to 90∘90^\circ (like 30∘30^\circ and 60∘60^\circ) give the same range.
x=ucos⁡θ t,y=usin⁡θ t−12gt2x=u\cos\theta\,t,\qquad y=u\sin\theta\,t-\tfrac12gt^2
where
uu
launch speed.
θ\theta
launch angle above horizontal.

2. Launched at an angle

Dropped and thrown together hit the ground at the same time
●●●●●●●●●●
At each instant the two balls are at the same height: horizontal motion does not affect vertical motion.
Worked example20 m s⁻¹ at 30°

Level ground.

Goal
Time of flight, range, maximum height.
Strategy
Components; vertical for time.
  1. ux=17.3, uy=10.0u_x=17.3,\ u_y=10.0
    20cos⁡30∘20\cos30^\circ, 20sin⁡30∘20\sin30^\circ.
  2. 0=10t−4.905t2⇒t=2.04 s0=10t-4.905t^2\Rightarrow t=2.04\text{ s}
    Back to y=0y=0.
  3. 17.3×2.04=35.3 m17.3\times2.04=35.3\text{ m}
    Range.
  4. 0=102−2(9.81)h⇒h=5.10 m0=10^2-2(9.81)h\Rightarrow h=5.10\text{ m}
    vy=0v_y=0 at the top.
Answer2.042.04 s; 35.335.3 m; 5.105.10 m.
✓ CheckRange formula u2sin⁡2θg=400(0.866)9.81=35.3\frac{u^2\sin2\theta}g=\frac{400(0.866)}{9.81}=35.3 ✓.

3. Horizontal launch

Worked exampleOff a 20 m cliff at 15 m s⁻¹

Horizontal launch.

Goal
Time, distance, impact velocity.
Strategy
Vertical from rest.
  1. 20=4.905t2⇒t=2.02 s20=4.905t^2\Rightarrow t=2.02\text{ s}
    Vertical.
  2. 15×2.02=30.3 m15\times2.02=30.3\text{ m}
    Horizontal.
  3. vy=9.81×2.02=19.8v_y=9.81\times2.02=19.8
    Final vertical speed.
  4. 152+19.82=24.8 m s−1 at 52.9∘\sqrt{15^2+19.8^2}=24.8\text{ m s}^{-1}\text{ at }52.9^\circ
    Recombine; below horizontal.
Answer2.022.02 s; 30.330.3 m; 24.824.8 m s−1^{-1} at 52.9∘52.9^\circ below horizontal.
✓ CheckEnergy: 12v2=12(225)+9.81(20)\frac12v^2=\frac12(225)+9.81(20) gives v=24.8v=24.8 ✓.
Edge caseAir resistance Reduces range and height; the path becomes asymmetric (steeper descent).
Common misconceptionZero velocity at the top Only the vertical component is zero; the horizontal ucos⁡θu\cos\theta remains.

Summary

  • Components.
  • Time links directions.
Key words
Projectile
Object moving under gravity alone after launch.
HistoryGalileo's parabola. Before Galileo, people thought a cannonball flew in a straight line, then suddenly dropped. In 16381638 he showed that combining steady horizontal motion with uniformly accelerated falling gives a parabola, and that 45∘45^\circ gives the longest range.
Fun factThe basketball "hang time". A great basketball dunker seems to hang in the air. But a vertical leap of 11 m means a time in the air of only about 0.90.9 s, and half of it is spent in the top quarter of the jump, where the player moves slowest. That's the "hang".
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