Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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17 questions

SA-9709-P1-TR5-0012 marksL1 FoundationCalculatorEquations
Solve sin⁡x=−0.5\sin x=-0.5 for 0∘≤x≤360∘0^\circ\le x\le360^\circ.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-Q011 markL1 FoundationCalculatorEquations
How many solutions does tan⁡x=1\tan x=1 have for 0∘≤x≤360∘0^\circ\le x\le360^\circ?
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-Q021 markL1 FoundationCalculatorUsing identities
Solving 2cos⁡2x−3cos⁡x−2=02\cos^2x-3\cos x-2=0 gives cos⁡x=−12\cos x=-\tfrac12 or cos⁡x=2\cos x=2. What should you do with cos⁡x=2\cos x=2?
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-G012 marksL1 FoundationCalculatorEquations
Solve sin⁡x=0.5\sin x=0.5 for 0∘≤x≤360∘0^\circ\le x\le360^\circ, step by step.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0043 marksL2 StandardCalculatorEquations
Solve tan⁡x=2\tan x=2 for 0∘≤x≤360∘0^\circ\le x\le360^\circ, giving answers to 1 decimal place.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0053 marksL2 StandardCalculatorEquations
Solve cos⁡x=−0.4\cos x=-0.4 for 0∘≤x≤360∘0^\circ\le x\le360^\circ, giving answers to 1 decimal place.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-0023 marksL2 StandardCalculatorTransformed angles
Solve cos⁡2x=0.5\cos2x=0.5 for 0∘≤x≤180∘0^\circ\le x\le180^\circ.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-0043 marksL2 StandardCalculatorUsing identities
Solve 2sin⁡x=cos⁡x2\sin x=\cos x for 0∘≤x≤360∘0^\circ\le x\le360^\circ, giving answers to 1 decimal place.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-0062 marksL2 StandardCalculatorEquations
Solve tan⁡x=3\tan x=\sqrt3 for 0≤x≤2π0\le x\le2\pi, giving exact answers in radians.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0064 marksL3 ExamCalculatorUsing identities
Solve 2sin⁡2x+3cos⁡x=02\sin^2x+3\cos x=0 for 0∘≤x≤360∘0^\circ\le x\le360^\circ.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0073 marksL3 ExamCalculatorTransformed angles
Solve sin⁡2x=0.6\sin2x=0.6 for 0∘≤x≤180∘0^\circ\le x\le180^\circ, giving answers to 1 decimal place.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0083 marksL3 ExamCalculatorTransformed angles
Solve tan⁡(x−30∘)=1\tan(x-30^\circ)=1 for 0∘≤x≤360∘0^\circ\le x\le360^\circ.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-0033 marksL3 ExamCalculatorTransformed angles
Solve sin⁡(x+30∘)=0.5\sin(x+30^\circ)=0.5 for 0∘≤x≤360∘0^\circ\le x\le360^\circ.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR5-0054 marksL3 ExamCalculatorUsing identities
Solve 3sin⁡2x=sin⁡x3\sin^2x=\sin x for 0∘≤x≤360∘0^\circ\le x\le360^\circ, giving answers to 1 decimal place where necessary.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0135 marksL4 ChallengingCalculatorEquations
Solve 3tan⁡2x−5tan⁡x−2=03\tan^2x-5\tan x-2=0 for 0∘≤x≤180∘0^\circ\le x\le180^\circ, giving answers to 1 decimal place.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0145 marksL4 ChallengingCalculatorUsing identities
Solve 2cos⁡x=3tan⁡x2\cos x=3\tan x for 0∘≤x≤360∘0^\circ\le x\le360^\circ.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-TR-0156 marksL5 ExtensionCalculatorEquations
Solve 2cos⁡2x=sin⁡x+12\cos^2x=\sin x+1 for 0≤x≤2π0\le x\le2\pi, giving exact answers in radians.

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Salam Academy Original Practice · Proposed mark scheme