Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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23 questions · page 1 of 2

SA-9709-P1-QD-0012 marksL1 FoundationCalculatora = 1
Express x2+6x+11x^2+6x+11 in the form (x+a)2+b(x+a)^2+b, where aa and bb are constants.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0022 marksL1 FoundationCalculatora = 1
Express x2−10x+4x^2-10x+4 in the form (x+a)2+b(x+a)^2+b.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0081 markL1 FoundationCalculatorVertex
What is the minimum value of (x−3)2+7(x-3)^2+7?
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0101 markL1 FoundationCalculatora = 1
Expand and simplify (x−3)2−4(x-3)^2-4. (Algebraic answers are checked for equivalence, so any correct form is accepted.)

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-G013 marksL1 FoundationCalculatora = 1
x2−4x+9=(x+p)2+qx^2-4x+9=(x+p)^2+q. Work through it in three steps.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-Q011 markL1 FoundationCalculatora = 1
x2+10xx^2+10x is equal to
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-Q021 markL1 FoundationCalculatorVertex
The vertex of y=(x+2)2−7y=(x+2)^2-7 is
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0033 marksL2 StandardCalculatora = 1
Express x2+5x−3x^2+5x-3 in the form (x+a)2+b(x+a)^2+b, giving aa and bb as exact fractions.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0043 marksL2 StandardCalculatora ≠ 1
Express 2x2−12x+52x^2-12x+5 in the form a(x+b)2+ca(x+b)^2+c.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0052 marksL2 StandardCalculatorVertex
Find the coordinates of the minimum point of the curve y=x2−8x+19y=x^2-8x+19.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0152 marksL2 StandardCalculatorVertex
The function gg is defined by g(x)=2(x+1)2−8g(x)=2(x+1)^2-8 for x∈Rx\in\mathbb{R}. State the equation of the line of symmetry of y=g(x)y=g(x) and the least value of g(x)g(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD1-0014 marksL2 StandardCalculatorSketching & models
For the curve y=x2−2x−8y=x^2-2x-8, find (a) the xx-coordinates where it crosses the xx-axis (b) where it crosses the yy-axis (c) the coordinates of its vertex. (These are what a sketch must show.)

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD1-0023 marksL2 StandardCalculatorVertex
Express −2x2+8x−3-2x^2+8x-3 in the form a(x+b)2+ca(x+b)^2+c, and hence find the greatest value of −2x2+8x−3-2x^2+8x-3.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD1-0042 marksL2 StandardCalculatora = 1
x2+bx+20≡(x−5)2+cx^2+bx+20\equiv(x-5)^2+c. Find bb and cc.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD1-0063 marksL2 StandardCalculatorSketching & models
A ball's height after tt seconds is h=20t−5t2h=20t-5t^2 metres. Find (a) its greatest height (b) the time at which this happens.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-Q031 markL2 StandardCalculatorUnknown constants
Which form shows directly that x2−6x+11>0x^2-6x+11>0 for all xx?
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0074 marksL3 ExamCalculatora ≠ 1
The function ff is defined by f(x)=3x2+12x+7f(x)=3x^2+12x+7 for x∈Rx\in\mathbb{R}.
(a) Express f(x)f(x) in the form a(x+b)2+ca(x+b)^2+c.
(b) Hence state the least value of f(x)f(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD1-0033 marksL3 ExamCalculatorUnknown constants
A parabola has its vertex at (2, −3)(2,\,-3) and passes through (0, 5)(0,\,5). Its equation is y=a(x−2)2−3y=a(x-2)^2-3. Find aa.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD1-0054 marksL3 ExamCalculatorSketching & models
A farmer has 4040 m of fencing to make three sides of a rectangular pen against a long straight wall. The two sides perpendicular to the wall are each xx m long. (a) Show that the area is A=x(40−2x)A=x(40-2x). (b) By completing the square, find the greatest possible area.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-QD-0093 marksL4 ChallengingCalculatorUnknown constants
Find the set of values of kk for which x2+6x+k>0x^2+6x+k>0 for all real values of xx.

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Salam Academy Original Practice · Proposed mark scheme