Practise questions · Salam Academy

SA-OC-MC-0021 markL1 FoundationCalculatorGas volumes

What volume, in

\mathrm{dm^3}

, does

0.25

mol of oxygen occupy at r.t.p.?

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SA-OC-MC-0012 marksL2 StandardCalculatorReacting masses

\mathrm{CaCO_3\rightarrow CaO+CO_2}

. What mass of

\mathrm{CaO}

(

M_r=56

) forms from

25

g of

\mathrm{CaCO_3}

(

M_r=100

)?

Salam Academy Original Practice · Proposed mark scheme

SA-OC-MC-0031 markL2 StandardCalculatorGas volumes

How many moles of gas are in

480\ \mathrm{cm^3}

at r.t.p.?

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SA-OC-MC-0042 marksL2 StandardCalculatorConcentration

0.10

mol of NaOH is dissolved to make

250\ \mathrm{cm^3}

of solution. Calculate the concentration in

\mathrm{mol/dm^3}

.

Salam Academy Original Practice · Proposed mark scheme

SA-OC-MC-0052 marksL2 StandardCalculatorConcentration

How many moles of HCl are in

20.0\ \mathrm{cm^3}

of

0.50\ \mathrm{mol/dm^3}

hydrochloric acid?

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SA-OC-MC-0062 marksL2 StandardCalculatorYield

The theoretical yield of a product is

40

g; the actual yield is

30

g. Calculate the percentage yield.

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SA-OC-MC-0092 marksL2 StandardCalculatorYield

A

5.0

g sample of impure limestone contains

4.0

g of calcium carbonate. Calculate the percentage purity.

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SA-OC-MC-0101 markL2 StandardCalculatorYield

1

mol of

\mathrm{N_2}

is mixed with

2

mol of

\mathrm{H_2}

:

\mathrm{N_2+3H_2\rightarrow2NH_3}

. The limiting reactant is

Salam Academy Original Practice · Proposed mark scheme

SA-OC-MC-0122 marksL2 StandardCalculatorConcentration

Convert

0.50\ \mathrm{mol/dm^3}

NaOH (

M_r=40

) into

\mathrm{g/dm^3}

.

Salam Academy Original Practice · Proposed mark scheme

SA-OC-MC-0073 marksL3 ExamCalculatorReacting masses

\mathrm{2Mg+O_2\rightarrow 2MgO}

. What mass of

\mathrm{MgO}

(

M_r=40

) forms when

6.0

g of Mg (

A_r=24

) burns completely?

Salam Academy Original Practice · Proposed mark scheme

SA-OC-MC-0083 marksL3 ExamCalculatorGas volumes

\mathrm{CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2}

. What volume of

\mathrm{CO_2}

, in

\mathrm{cm^3}

at r.t.p., forms from

2.0

g of

\mathrm{CaCO_3}

(

M_r=100

)?

Salam Academy Original Practice · Proposed mark scheme

SA-OC-MC-0113 marksL3 ExamCalculatorConcentration

25.0\ \mathrm{cm^3}

of NaOH is neutralised by

12.5\ \mathrm{cm^3}

of

0.200\ \mathrm{mol/dm^3}

\mathrm{H_2SO_4}

.

\mathrm{H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O}

. Calculate

c(\mathrm{NaOH})

in

\mathrm{mol/dm^3}

.

Salam Academy Original Practice · Proposed mark scheme

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