PractiseQuestion bank
Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.
Sign in to check answers. Your attempts build your mastery and error book.
13 questions
SA-9709-P3-I35-0081 markL1 FoundationCalculatorChanging limits
With u=x2+1, the limits x=0 and x=2 become Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-G013 marksL1 FoundationCalculatorRecognising
Use the substitution u=x2+1 to find ∫2x(x2+1)4dx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-Q011 markL1 FoundationCalculatorRecognising
The best substitution for ∫x(x2−3)7dx is Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0013 marksL2 StandardCalculatorSubstitution
Use the substitution u=x2+4 to find ∫xx2+4dx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0024 marksL2 StandardCalculatorChanging limits
Use the substitution u=x2+1 to find the exact value of ∫01(x2+1)2xdx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0032 marksL2 StandardCalculatorRecognising
Find ∫cosxesinxdx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0043 marksL2 StandardCalculatorChanging limits
Use the substitution u=sinx to find the exact value of ∫0π/2cosxsin2xdx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-IN-0104 marksL2 StandardCalculatorChanging limits
Use the substitution u=x2+1 to find ∫01x(x2+1)3dx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0073 marksL3 ExamCalculatorRecognising
Use the substitution u=1+ex to find ∫(1+ex)2exdx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-IN-0124 marksL3 ExamCalculatorSubstitution
Use the substitution u=cosx to find ∫0π/2sinxcos3xdx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0065 marksL4 ChallengingCalculatorSubstitution
Use the substitution u=x+1 to find the exact value of ∫03x+1xdx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-IN-0115 marksL4 ChallengingCalculatorChanging limits
Use the substitution u=1+x to find the exact value of ∫14x(1+x)1dx. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-I35-0055 marksL5 ExtensionCalculatorSubstitution
Use the substitution u=2x−1 to find the exact value of ∫1/21x(2x−1)5dx. Salam Academy Original Practice · Proposed mark scheme