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Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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13 questions

SA-9709-P1-IN2-0012 marksL1 FoundationCalculator(ax + b)ⁿ
Find ∫(2x−5)3 dx\displaystyle\int(2x-5)^3\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-G012 marksL1 FoundationCalculator(ax + b)ⁿ
Find ∫(3x+1)4 dx\displaystyle\int(3x+1)^4\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-Q011 markL1 FoundationCalculator(ax + b)ⁿ
For n≠−1n\neq-1, ∫(ax+b)n dx\displaystyle\int(ax+b)^n\,dx is
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN-Q031 markL1 FoundationCalculator(ax + b)ⁿ
∫(2x+1)3 dx\displaystyle\int(2x+1)^3\,dx is
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN-0032 marksL2 StandardCalculator(ax + b)ⁿ
Find ∫(2x+3)4 dx\displaystyle\int(2x+3)^4\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-0022 marksL2 StandardCalculator(ax + b)ⁿ
Find ∫(1−x)5 dx\displaystyle\int(1-x)^5\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-0032 marksL2 StandardCalculatorRoots and reciprocals
Find ∫2x+1 dx\displaystyle\int\sqrt{2x+1}\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-0042 marksL2 StandardCalculatorRoots and reciprocals
Find ∫4(2x+3)3 dx\displaystyle\int\frac{4}{(2x+3)^3}\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN-0043 marksL3 ExamCalculatorRoots and reciprocals
Find ∫6(3x−2)2 dx\displaystyle\int\frac{6}{(3x-2)^2}\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN-0154 marksL3 ExamCalculatorFinding the curve
A curve has gradient dydx=4x+1\dfrac{dy}{dx}=\sqrt{4x+1} and passes through (2,10)(2,10). The equation of the curve is y=(4x+1)326+cy=\dfrac{(4x+1)^{\frac32}}{6}+c. Find cc.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-0052 marksL3 ExamCalculatorRoots and reciprocals
Find ∫14x−3 dx\displaystyle\int\frac{1}{\sqrt{4x-3}}\,dx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-0064 marksL3 ExamCalculatorFinding the curve
A curve has dydx=(2x−1)2\dfrac{dy}{dx}=(2x-1)^2 and passes through (1,1)(1,1). Find the equation of the curve.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-IN2-0074 marksL4 ChallengingCalculatorFinding the curve
A curve has dydx=6(3x+1)2\dfrac{dy}{dx}=\dfrac{6}{(3x+1)^2} and passes through (1,2)(1,2). Find the equation of the curve.

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Salam Academy Original Practice · Proposed mark scheme