Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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18 questions

SA-9709-P1-FN2-0012 marksL1 FoundationCalculatorEvaluate fg(a)
f(x)=2x+3f(x)=2x+3 and g(x)=x2−1g(x)=x^2-1. Find gf(2)gf(2).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0042 marksL1 FoundationCalculatorExpressions
f(x)=2x+3f(x)=2x+3. Find an expression for ff(x)ff(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-G012 marksL1 FoundationCalculatorEvaluate fg(a)
f(x)=2x+3f(x)=2x+3 and g(x)=x2−1g(x)=x^2-1. Find fg(2)fg(2).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-Q011 markL1 FoundationCalculatorEvaluate fg(a)
To work out fg(x)fg(x) you apply
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-Q021 markL1 FoundationCalculatorExistence & range
The composite fgfg exists when
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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-Q031 markL1 FoundationCalculatorExpressions
For a function ff, the notation f2(x)f^2(x) means
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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0022 marksL2 StandardCalculatorExpressions
f(x)=2x+3f(x)=2x+3 and g(x)=x2−1g(x)=x^2-1. Find an expression for fg(x)fg(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0032 marksL2 StandardCalculatorExpressions
f(x)=2x+3f(x)=2x+3 and g(x)=x2−1g(x)=x^2-1. Find an expression for gf(x)gf(x), simplified.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0053 marksL2 StandardCalculatorExpressions
f(x)=2x+3f(x)=2x+3 and g(x)=x2−1g(x)=x^2-1. Solve fg(x)=19fg(x)=19.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0071 markL2 StandardCalculatorExistence & range
f(x)=x−1f(x)=\sqrt{x-1} for x≥1x\ge1, and g(x)=3−x2g(x)=3-x^2 for x∈Rx\in\mathbb{R}. Which statement is true?
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0092 marksL2 StandardCalculatorExpressions
f(x)=x2+2f(x)=x^2+2 for x∈Rx\in\mathbb{R}, and g(x)=1x−1g(x)=\dfrac{1}{x-1} for x≠1x\ne1. Find an expression for gf(x)gf(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0143 marksL2 StandardCalculatorExistence & range
f(x)=x+4f(x)=x+4 and g(x)=xg(x)=\sqrt x. (i) Find gf(5)gf(5). (ii) gf(x)gf(x) is defined for x≥kx\ge k. Find kk.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0063 marksL3 ExamCalculatorExpressions
f(x)=2x+3f(x)=2x+3 and g(x)=x2−1g(x)=x^2-1. Solve gf(x)=0gf(x)=0.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0082 marksL3 ExamCalculatorExistence & range
f(x)=x−1f(x)=\sqrt{x-1} for x≥1x\ge1, and g(x)=x+kg(x)=x+k for x≥0x\ge0. Find the least value of kk for which fgfg exists.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0102 marksL3 ExamCalculatorExistence & range
With gf(x)=1x2+1gf(x)=\dfrac{1}{x^2+1} for x∈Rx\in\mathbb{R}, find the greatest value of gf(x)gf(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0123 marksL3 ExamCalculatorExpressions
f(x)=x−5f(x)=x-5 and g(x)=x2g(x)=x^2. Find the value of xx for which fg(x)=gf(x)fg(x)=gf(x).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0114 marksL4 ChallengingCalculatorExpressions
f(x)=ax+bf(x)=ax+b, where a>0a>0. Given that ff(x)=9x−8ff(x)=9x-8, find aa and bb.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-FN2-0135 marksL5 ExtensionCalculatorExistence & range
f(x)=3x−1f(x)=3x-1 for 0≤x≤10\le x\le1, and g(x)=x2+2xg(x)=x^2+2x for x∈Rx\in\mathbb{R}. The range of gfgf is p≤gf(x)≤qp\le gf(x)\le q. Find pp and qq.

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Salam Academy Original Practice · Proposed mark scheme