Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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12 questions

SA-9709-P3-DE3-G014 marksL1 FoundationCalculatorParticular solutions
Solve dydx=2yx\dfrac{dy}{dx}=\dfrac{2y}{x} for x>0x>0, given that y=3y=3 when x=1x=1. Give yy in terms of xx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-Q011 markL1 FoundationCalculatorHarder integrals
After separating dydx=yx2−1\dfrac{dy}{dx}=\dfrac{y}{x^2-1}, the xx integral is best done by
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE-Q031 markL1 FoundationCalculatorParticular solutions
A particular solution differs from the general solution because it
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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE-0113 marksL2 StandardCalculatorParticular solutions
Given dydx=3y\dfrac{dy}{dx}=3y and y=2y=2 when x=0x=0, find the exact value of yy when x=1x=1.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0034 marksL2 StandardCalculatorHarder integrals
Solve dydx=ytan⁡x\dfrac{dy}{dx}=y\tan x for −π2<x<π2-\tfrac\pi2<x<\tfrac\pi2, given that y=2y=2 when x=0x=0. Give yy in terms of xx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0016 marksL3 ExamCalculatorHarder integrals
Solve ydydx=xexy\dfrac{dy}{dx}=xe^x, given that y=2y=2 when x=0x=0 and y>0y>0. Give yy in terms of xx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0026 marksL3 ExamCalculatorHarder integrals
Solve dydx=2yx(x+2)\dfrac{dy}{dx}=\dfrac{2y}{x(x+2)} for x>0x>0, given that y=1y=1 when x=2x=2. Give yy in terms of xx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0046 marksL3 ExamCalculatorHarder integrals
Solve ydydx=cos⁡2xy\dfrac{dy}{dx}=\cos^2x, given that y=1y=1 when x=0x=0 and y>0y>0. Find the exact value of yy when x=π2x=\tfrac\pi2.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0065 marksL3 ExamCalculatorParticular solutions
Solve (1+x2)dydx=xy(1+x^2)\dfrac{dy}{dx}=xy, given that y=3y=3 when x=0x=0 and y>0y>0. Find the value of yy when x=3x=\sqrt3.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0056 marksL4 ChallengingCalculatorHarder integrals
Solve dydx=e2ycos⁡x\dfrac{dy}{dx}=e^{2y}\cos x, given that y=0y=0 when x=0x=0. Give yy in terms of xx.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE-0097 marksL5 ExtensionCalculatorHarder integrals
Solve dydx=y(x+1)(x+2)\dfrac{dy}{dx}=\dfrac{y}{(x+1)(x+2)} for x≥0x\ge0, given that y=1y=1 when x=0x=0. Give yy in terms of xx, and state the value that yy approaches as xx becomes large.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P3-DE3-0076 marksL5 ExtensionCalculatorHarder integrals
Solve dydx=x(1+y2)\dfrac{dy}{dx}=x(1+y^2), given that y=0y=0 when x=0x=0. Find yy when x=1x=1, correct to 3 significant figures, and the smallest positive value of xx at which the solution stops existing.

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Salam Academy Original Practice · Proposed mark scheme