Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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18 questions

SA-9709-P1-CG-0012 marksL1 FoundationCalculatorEquations
Find the equation of the line with gradient 33 passing through (2, −1)(2,\,-1), in the form y=mx+cy=mx+c.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-0032 marksL1 FoundationCalculatorEquations
The line LL has equation 3x+4y=123x+4y=12. State the gradient of LL and the yy-coordinate where LL crosses the yy-axis.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0012 marksL1 FoundationCalculatorGradient & midpoint
Find the gradient of the line through (−3,4)(-3,4) and (5,−2)(5,-2).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0022 marksL1 FoundationCalculatorGradient & midpoint
Find the midpoint of (−4,7)(-4,7) and (6,−3)(6,-3).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0042 marksL1 FoundationCalculatorGradient & midpoint
Find the distance between (2,−1)(2,-1) and (8,7)(8,7).

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0082 marksL1 FoundationCalculatorIntersections
Find the point of intersection of the lines 2x+y=72x+y=7 and x−y=2x-y=2.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-Q011 markL1 FoundationCalculatorEquations
The gradient of the line y=5−3xy=5-3x is
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-Q021 markL1 FoundationCalculatorEquations
The line through (2,−4)(2,-4) parallel to the xx-axis has equation
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-Q031 markL1 FoundationCalculatorGradient & midpoint
The midpoint of (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) is
Choose one option

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-G014 marksL1 FoundationCalculatorEquations
AA is (1, 2)(1,\,2) and BB is (5, 10)(5,\,10). Find the gradient of ABAB, the midpoint of ABAB, and the length of ABAB in exact form.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-0043 marksL2 StandardCalculatorEquations
Find the point of intersection of the lines y=2x−1y=2x-1 and x+3y=11x+3y=11.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-0143 marksL2 StandardCalculatorEquations
The distance between P(k, 3)P(k,\,3) and Q(4, −1)Q(4,\,-1) is 55. Find the possible values of kk.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0032 marksL2 StandardCalculatorGradient & midpoint
M(3,5)M(3,5) is the midpoint of ABAB, where AA is (1,2)(1,2). Find the coordinates of BB.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0053 marksL2 StandardCalculatorEquations
Find the equation of the line through (1,2)(1,2) and (4,11)(4,11), in the form y=mx+cy=mx+c.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0062 marksL2 StandardCalculatorEquations
The line y=23x−4y=\tfrac23x-4 can be written as 2x+by+c=02x+by+c=0, where bb and cc are integers. Find bb and cc.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0073 marksL2 StandardCalculatorIntersections
The points (1,3)(1,3), (3,7)(3,7) and (6,k)(6,k) lie on a straight line. Find kk.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0093 marksL2 StandardCalculatorIntersections
The line y=2x+4y=2x+4 crosses the xx-axis at PP and the yy-axis at QQ. Find the area of triangle OPQOPQ, where OO is the origin.

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Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG1-0105 marksL5 ExtensionCalculatorGradient & midpoint
AA is (0,2)(0,2) and BB is (6,5)(6,5). The point CC lies on the xx-axis and is the same distance from AA as from BB. Find the xx-coordinate of CC.

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Salam Academy Original Practice · Proposed mark scheme