PractiseQuestion bank
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17 questions
SA-9709-P1-CG2-0012 marksL1 FoundationCalculatorGradients
Find the equation of the line parallel to y=4x−1 that passes through (2,3), in the form y=mx+c. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0041 markL1 FoundationCalculatorGradients
Are the lines y=2x+1 and x+2y=5 perpendicular? Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-G011 markL1 FoundationCalculatorGradients
A line has gradient 52. State the gradient of a line perpendicular to it. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-Q011 markL1 FoundationCalculatorGradients
Two lines are perpendicular. The product of their gradients is
Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-Q021 markL1 FoundationCalculatorGradients
Which line is parallel to y=3x+2? Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-Q011 markL1 FoundationCalculatorGradients
A line is perpendicular to a line with gradient 32. Its gradient is Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-0024 marksL2 StandardCalculatorGradients
A is (−2,3) and B is (4,7). Find the equation of the perpendicular bisector of AB, in the form y=mx+c. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-0133 marksL2 StandardCalculatorGradients
Find the equation of the line through (5,1) that is parallel to 2x−5y=3, in the form y=mx+c. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0022 marksL2 StandardCalculatorGradients
Find the equation of the line through (1,4) perpendicular to y=−31x+2, in the form y=mx+c. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0033 marksL2 StandardCalculatorGradients
Find the equation of the line through (4,1) perpendicular to 2x+3y=6, in the form y=mx+c. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0052 marksL2 StandardCalculatorGradients
The lines y=kx+1 and y=41x are perpendicular. Find k. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0064 marksL2 StandardCalculatorBisectors
Find the equation of the perpendicular bisector of A(2,1) and B(6,9), in the form y=mx+c. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0082 marksL2 StandardCalculatorShapes
A(1,1), B(4,5) and C(8,2) form a triangle. At which vertex is there a right angle? Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0074 marksL3 ExamCalculatorBisectors
Find the coordinates of the foot of the perpendicular from P(5,5) to the line y=x−2. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0093 marksL3 ExamCalculatorShapes
ABCD is a parallelogram with A(0,0), B(4,2) and C(2,6). Find the coordinates of D. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG-0155 marksL4 ChallengingCalculatorGradients
A is (1,1) and B is (7,3). The line through A perpendicular to AB meets the y-axis at C. Find the y-coordinate of C and the area of triangle ABC. Salam Academy Original Practice · Proposed mark scheme
SA-9709-P1-CG2-0106 marksL5 ExtensionCalculatorBisectors
A is (1,2) and B is (5,6). The perpendicular bisector of AB meets the x-axis at P. (i) Find the x-coordinate of P. (ii) Find the area of triangle ABP. Salam Academy Original Practice · Proposed mark scheme