Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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12 questions

SA-9702-QP2-0012 marksL1 FoundationCalculatorde Broglie wavelength
Calculate the de Broglie wavelength of an electron moving at 2.0×1062.0\times10^6 m s⁻¹, in nm. (h=6.63×10−34h=6.63\times10^{-34} J s; me=9.11×10−31m_e=9.11\times10^{-31} kg)

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0031 markL1 FoundationCalculatorDuality evidence
Evidence for the wave nature of electrons comes from
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0041 markL1 FoundationCalculatorDuality evidence
Evidence for the particle nature of electromagnetic radiation comes from
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0061 markL1 FoundationCalculatorde Broglie wavelength
The speed of an electron doubles. State the factor by which its de Broglie wavelength changes, as a decimal.

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0101 markL1 FoundationCalculatorde Broglie wavelength
A proton and an electron have the same speed. The proton's de Broglie wavelength is
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0121 markL1 FoundationCalculatorde Broglie wavelength
The de Broglie wavelength of a particle is equal to
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0022 marksL2 StandardCalculatorde Broglie wavelength
Electrons are accelerated from rest through 50005000 V. Calculate their de Broglie wavelength, in units of 10−1110^{-11} m. (h=6.63×10−34h=6.63\times10^{-34} J s; me=9.11×10−31m_e=9.11\times10^{-31} kg; e=1.60×10−19e=1.60\times10^{-19} C)

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0051 markL2 StandardCalculatorDuality evidence
In an electron diffraction tube, the accelerating p.d. is increased. The rings on the screen
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0071 markL2 StandardCalculatorde Broglie wavelength
The accelerating p.d. for an electron beam is increased by a factor of 44. State the factor by which the de Broglie wavelength changes, as a decimal.

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0081 markL2 StandardCalculatorDuality evidence
Graphite is used in electron diffraction experiments because
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0091 markL2 StandardCalculatorde Broglie wavelength
Calculate the speed of an electron with a de Broglie wavelength of 1.0×10−101.0\times10^{-10} m, in units of 10610^6 m s⁻¹. (h=6.63×10−34h=6.63\times10^{-34} J s; me=9.11×10−31m_e=9.11\times10^{-31} kg)

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-QP2-0113 marksL3 ExamCalculatorde Broglie wavelength
Calculate the p.d. through which electrons must be accelerated from rest to have a de Broglie wavelength of 1.0×10−101.0\times10^{-10} m. (h=6.63×10−34h=6.63\times10^{-34} J s; me=9.11×10−31m_e=9.11\times10^{-31} kg; e=1.60×10−19e=1.60\times10^{-19} C)

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Salam Academy Original Practice · Proposed mark scheme