Salam Academy
Practise

Question bank

Original exam-style questions, mapped to your syllabus. Answers are checked for mathematical equivalence and every attempt updates your mastery.

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12 questions

SA-9702-AC2-0011 markL1 FoundationCalculatorRectification
Half-wave rectification can be achieved using
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0031 markL1 FoundationCalculatorRectification
A 5050 Hz supply is full-wave rectified. State the frequency of the peaks in the output.

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0041 markL1 FoundationCalculatorSmoothing
The smoothing capacitor in a rectifier circuit is connected
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0061 markL1 FoundationCalculatorRectification
State the number of diodes needed for a bridge rectifier.

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0101 markL1 FoundationCalculatorRectification
A diode is used in rectification because it
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0121 markL1 FoundationCalculatorRectification
Compared with half-wave rectification, full-wave rectification
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0022 marksL2 StandardCalculatorSmoothing
A 470470 μF smoothing capacitor is connected across a 1.01.0 kΩ load. Calculate the time constant.

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0051 markL2 StandardCalculatorSmoothing
Which change would reduce the ripple in a smoothed output?
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0071 markL2 StandardCalculatorRectification
In a bridge rectifier, during each half-cycle
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0081 markL2 StandardCalculatorSmoothing
Between peaks, the output of a smoothed rectifier falls because
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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0091 markL2 StandardCalculatorSmoothing
A full-wave rectified 5050 Hz supply has peaks every 1010 ms. The load is 2.02.0 kΩ. Calculate the capacitance needed for RCRC to be 5050 times the time between peaks, in μF.

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Salam Academy Original Practice · Proposed mark scheme
SA-9702-AC2-0113 marksL3 ExamCalculatorSmoothing
A smoothing capacitor charges to a peak of 12.012.0 V, then discharges through the load with RC=0.20RC=0.20 s for 1010 ms until the next peak. Calculate the ripple voltage (the drop in that time), in V.

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Salam Academy Original Practice · Proposed mark scheme