Doubling [A] quadruples the rate. The order with respect to A is
Salam Academy Original Practice · Proposed mark scheme
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Tripling [B] has no effect on the rate. The order with respect to B is
Salam Academy Original Practice · Proposed mark scheme
A first-order reaction has k = 0.0231 s⁻¹. Calculate its half-life (s).
Salam Academy Original Practice · Proposed mark scheme
The units of k for a second-order reaction are
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A concentration–time graph is a straight line with negative gradient. The reaction is
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For rate = k[(CH₃)₃CBr], the hydrolysis mechanism is
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Overall order of rate = k[A]²[B]?
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On a plot of ln k against 1/T, the gradient equals
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For a first-order reaction, halving the starting concentration makes the half-life
Salam Academy Original Practice · Proposed mark scheme
rate = k[A][B]². When [A] = 0.10 and [B] = 0.20 mol dm⁻³, rate = 3.0 × 10⁻³ mol dm⁻³ s⁻¹. Calculate k (dm⁶ mol⁻² s⁻¹).
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rate = k[NO₂]² for . A possible slow step is
Salam Academy Original Practice · Proposed mark scheme
The gradient of ln k against 1/T is −6000 K. Calculate (kJ mol⁻¹). R = 8.31 J K⁻¹ mol⁻¹.
Salam Academy Original Practice · Proposed mark scheme