Practise questions · Salam Academy

SA-AC-MC-0012 marksL1 FoundationCalculatorTitrations

25.0\ \text{cm}^3

of NaOH is neutralised by

21.40\ \text{cm}^3

of

0.100\ \text{mol dm}^{-3}

HCl. Calculate

c(\text{NaOH})

.

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0121 markL1 FoundationCalculatorTitrations

How many moles of solute are in

200\ \text{cm}^3

of

0.150\ \text{mol dm}^{-3}

solution?

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0023 marksL2 StandardCalculatorTitrations

25.0\ \text{cm}^3

of

\mathrm{Na_2CO_3}

needs

23.50\ \text{cm}^3

of

0.150\ \text{mol dm}^{-3}

HCl.

\mathrm{Na_2CO_3+2HCl\rightarrow2NaCl+H_2O+CO_2}

. Calculate

c(\mathrm{Na_2CO_3})

.

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0033 marksL2 StandardCalculatorReacting masses

5.00

g of

\mathrm{CaCO_3}

(

M_r=100

) reacts with excess HCl. What volume of CO₂ forms at r.t.p., in cm³?

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SA-AC-MC-0041 markL2 StandardCalculatorReacting masses

0.10

mol

\mathrm{N_2}

and

0.24

mol

\mathrm{H_2}

react:

\mathrm{N_2+3H_2\rightarrow2NH_3}

. The limiting reagent is

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0052 marksL2 StandardCalculatorReacting masses

Using

0.24

mol

\mathrm{H_2}

(limiting) in

\mathrm{N_2+3H_2\rightarrow2NH_3}

, what is the maximum moles of

\mathrm{NH_3}

?

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0073 marksL2 StandardCalculatorTitrations

25.0\ \text{cm}^3

aliquots from a

250\ \text{cm}^3

solution of an acid each contain

2.00\times10^{-3}

mol of acid. The solution was made from

1.80

g of the acid. Calculate the

M_r

of the acid.

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0082 marksL2 StandardCalculatorReacting masses

Theoretical yield is

12.0

g; actual yield

9.30

g. Calculate the percentage yield.

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0092 marksL2 StandardCalculatorTitrations

Convert

0.250\ \text{mol dm}^{-3}

sulfuric acid (

M_r=98.1

) into g dm⁻³.

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0101 markL2 StandardCalculatorBack titration

A back titration is used when the substance being analysed

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0064 marksL3 ExamCalculatorBack titration

A

0.500

g antacid tablet (CaCO₃) is added to

50.0\ \text{cm}^3

of

0.500\ \text{mol dm}^{-3}

HCl. The excess acid needs

32.0\ \text{cm}^3

of

0.500\ \text{mol dm}^{-3}

NaOH. Calculate the mass of CaCO₃ in the tablet (

M_r=100

).

Salam Academy Original Practice · Proposed mark scheme

SA-AC-MC-0113 marksL3 ExamCalculatorReacting masses

0.0100

mol of metal M reacts with exactly

0.0300

mol of HCl, giving H₂. What is the charge on the metal ion formed? Enter the number.

Salam Academy Original Practice · Proposed mark scheme

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