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Nuclear and particle physics · Subtopic 3 of 4

Particle Interactions

Every particle has an antiparticle with the same mass and opposite charge. They can annihilate into photons, and a photon with enough energy can create a particle–antiparticle pair: Emin⁡=2mc2E_{\min}=2mc^2. Forces act by exchange particles (photon, W bosons, gluons). A reaction can happen only if charge, baryon number and lepton number are all conserved; strangeness is conserved in strong interactions.

Edexcel YPH11 WPH14AQA 7408 Paper 1≈ 45 minRevision 1 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Describe annihilation and pair production and calculate photon energies.
  • Name the four interactions and their exchange particles.
  • Draw simple interaction diagrams for β decay and electron capture.
  • Use conservation laws to decide whether a reaction can occur.
Pause and think

A PET scanner detects two gamma photons flying apart in opposite directions. Why opposite?

Section 2 of 14

Core idea

Start hereMatter from light

A gamma-ray photon passes close to a nucleus and vanishes. In its place appear an electron and a positron. Energy has turned into matter, and antimatter, exactly as E=mc2E=mc^2 allows.

The big idea

Particles interact by exchanging other particles. Every reaction must conserve charge, baryon number and lepton number (and strangeness, for strong interactions).

1. Antimatter

Threshold for pair production
  1. Eγ≥mc2+mc2E_\gamma\ge m c^2+mc^2
    Both particles need their rest energy.
  2. Emin⁡=2mc2E_{\min}=2mc^2
    Any extra becomes kinetic energy.
  3. e−e+: 2×0.511=1.022 MeVe^-e^+:\ 2\times0.511=1.022\text{ MeV}
    Electron rest energy.
A nucleus nearby takes up momentum, which is why pair production happens near nuclei.
Worked exampleAnnihilation photons

An electron and positron at rest annihilate.

Goal
Photon frequency.
Strategy
Each photon gets mc2mc^2.
  1. E=0.511 MeV=8.19×10−14 JE=0.511\text{ MeV}=8.19\times10^{-14}\text{ J}
    Rest energy each.
  2. f=Eh=8.19×10−146.63×10−34f=\frac Eh=\frac{8.19\times10^{-14}}{6.63\times10^{-34}}
    E=hfE=hf.
  3. f=1.24×1020 Hzf=1.24\times10^{20}\text{ Hz}
    Gamma rays.
AnswerTwo 1.24×10201.24\times10^{20} Hz photons, back to back.
✓ CheckZero total momentum before and after ✓.

2. Forces and conservation

Interactions and exchange particles

Each interaction has its own carrier.

Worked exampleTesting a reaction

Is p+p→p+π+p+p\to p+\pi^+ possible?

Goal
Yes or no.
Strategy
Tabulate QQ, BB, LL.
  1. Q: 2→2 ✓Q:\ 2\to2\ \checkmark
    Charge.
  2. B: 2→1 ×B:\ 2\to1\ \times
    Pions are mesons, B=0B=0.
AnswerForbidden: baryon number not conserved.
✓ Checkp+p→p+n+π+p+p\to p+n+\pi^+ would conserve BB ✓.
Common misconceptionNeutrino or antineutrino? β⁻ makes an electron (L=+1L=+1), so it must also make an antineutrino (L=−1L=-1).
Key takeawayStrangeness Strange particles are made in pairs by the strong interaction but decay one at a time by the weak interaction.
Pause and think

Why is electron capture (p+e−→n+νep+e^-\to n+\nu_e) a weak interaction?

Summary

  • Emin⁡=2mc2E_{\min}=2mc^2.
  • Exchange particles carry forces.
  • Conserve QQ, BB, LL.
  • SS conserved only in strong.
Key words
Antiparticle
Same mass, opposite charge and quantum numbers.
Annihilation
Particle and antiparticle become photons.
Exchange particle
Virtual particle that carries an interaction.
HistoryDirac and the positron. Paul Dirac's 1928 equation predicted a positive electron. Carl Anderson photographed one in a cloud chamber in 1932, and antimatter became real.
Fun factBananas emit antimatter. Potassium-40 in a banana occasionally decays by β+^+, emitting a positron roughly once every 75 minutes.
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