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LearnYMA01WMA11 · Pure Mathematics 1IntegrationFinding a curve from its gradient
Integration · Subtopic 3 of 3

Finding a Curve from its Gradient

Integrating a gradient function gives a whole family of curves, f(x)+cf(x)+c. One known point picks out the single curve you want: substitute the point and solve for cc.

Edexcel YMA01 WMA11≈ 30 minRevision 6 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Integrate f′(x)f'(x) to get f(x)+cf(x)+c.
  • Use a given point to find cc.
  • Use the resulting function to find other values.
  • Find unknown constants inside the gradient function.
Pause and think

You know your speed at every moment of a journey but not where you started. Can you say exactly where you are now?

Section 2 of 14

Core idea

Start hereWhich curve?

Integrating dydx\frac{dy}{dx} gives a whole family of curves stacked vertically. Tell me one point the curve passes through and exactly one family member fits.

The big idea

Integrate f′(x)f'(x) to get f(x)+cf(x)+c; substitute a known point to find cc.

1. Fixing the constant

dy/dx = 3x² − 4: only one curve passes through (2, 5)
−3−2−1123−6−4−22468100xyy = x³ − 4x + 5(2, 5)
The whole family y=x3−4x+cy=x^3-4x+c has the right gradient; the point (2,5)(2,5) picks out c=5c=5.
Worked exampledydx=3x2−4\frac{dy}{dx}=3x^2-4 through (2,5)(2,5)

Find the curve.

Goal
y=f(x)y=f(x).
Strategy
Integrate, substitute.
  1. y=x3−4x+cy=x^3-4x+c
    Integrate.
  2. 5=8−8+c⇒c=55=8-8+c\Rightarrow c=5
    Point (2,5)(2,5).
Answery=x3−4x+5y=x^3-4x+5.
✓ Checky(2)=8−8+5=5y(2)=8-8+5=5 ✓; derivative 3x2−43x^2-4 ✓.
Worked examplef′(x)=6xf'(x)=\frac6{\sqrt x}, f(4)=30f(4)=30

Find f(x)f(x).

Goal
Function.
Strategy
6x−1/26x^{-1/2}.
  1. f(x)=6x1/21/2+c=12x+cf(x)=\frac{6x^{1/2}}{1/2}+c=12\sqrt x+c
    Integrate.
  2. 24+c=30⇒c=624+c=30\Rightarrow c=6
    124=2412\sqrt4=24.
Answerf(x)=12x+6f(x)=12\sqrt x+6.
✓ Checkf(4)=30f(4)=30 ✓.
Common misconceptionForgetting c Without cc you cannot use the point, and the answer is wrong.
Pause and think

dydx=2x\frac{dy}{dx}=2x, curve through (1,4)(1,4)?

Summary

  • Integrate, then use the point.
Key words
Particular solution
The one curve fitting a given point.
HistoryThe fundamental theorem. Isaac Barrow, Newton's teacher at Cambridge, was among the first to see that finding areas and finding tangents are inverse processes. Newton and Leibniz turned that insight into the fundamental theorem of calculus.
Fun factReconstructing a flight path. If a plane's black-box recorder logs its rate of climb, investigators can integrate it to reconstruct the plane's height over time, provided they know its height at one moment (usually take-off).
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