NMR Spectroscopy
NMR detects nuclei (¹H, ¹³C) in a magnetic field; each environment gives a signal at a chemical shift δ (ppm) relative to TMS (δ = 0). Samples are dissolved in CDCl₃ (no ¹H signal). ¹³C NMR: number of peaks = number of carbon environments; shift identifies type (C=O 160–220; C–O 50–90; aromatic 110–160). ¹H NMR: number of peaks = H environments; integration gives the ratio of H atoms; splitting follows the n + 1 rule (n = H on neighbouring carbons): singlet, doublet, triplet, quartet. O–H/N–H peaks disappear on shaking with D₂O. Combine with IR and mass spectra to identify unknowns.
Learning objectives
- Count carbon environments and use ¹³C shifts.
- Interpret ¹H shift, integration and splitting.
- Explain the roles of TMS, CDCl₃ and D₂O.
- Deduce structures from combined data.
Why does ethanol's CH₃ appear as a triplet and CH₂ as a quartet?
Core idea
NMR tells you how many kinds of hydrogen a molecule has, how many of each, and what is next door.
Each environment gives a peak at a chemical shift. In ¹H NMR, peak area gives the number of H and splitting (n + 1) gives the number of neighbouring H.
Four pieces of information.
δ 1.2 (3H, t), δ 2.4 (2H, q), δ 11.5 (1H, s, gone with D₂O).
- Goal
- Structure.
- Strategy
- Assign each peak.
- Ethyl pattern.
- Acid proton.
Summary
- ¹³C: environments and shift.
- ¹H: shift, integration, n + 1.
- D₂O removes OH/NH peaks.
- Chemical shift
- Position of a peak (ppm) relative to TMS.
- Spin–spin splitting
- Peak split into n + 1 lines by n neighbouring H.
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