Salam Academy
WCH14 · Module

Acid-base equilibria

2 subtopics≈ 95 min in total
  1. pH, Ka and buffers

    pH=−log⁡[H+]\mathrm{pH}=-\log[\mathrm{H^+}]. Strong acids: [H+]=[\mathrm{H^+}]= acid concentration (× number of H⁺). Water: Kw=[H+][OH−]=1.00×10−14K_w=[\mathrm{H^+}][\mathrm{OH^-}]=1.00\times10^{-14} at 298 K; for strong bases, [H+]=Kw/[OH−][\mathrm{H^+}]=K_w/[\mathrm{OH^-}]. Weak acids: Ka=[H+][A−][HA]K_a=\frac{[\mathrm{H^+}][\mathrm{A^-}]}{[\mathrm{HA}]}; assume [H+]=[A−][\mathrm{H^+}]=[\mathrm{A^-}], so [H+]=Ka[HA][\mathrm{H^+}]=\sqrt{K_a[\mathrm{HA}]}; pKa=−log⁡Ka\mathrm{p}K_a=-\log K_a. A buffer (weak acid + its salt) resists pH change: [H+]=Ka[HA][A−][\mathrm{H^+}]=K_a\frac{[\mathrm{HA}]}{[\mathrm{A^-}]}, or pH=pKa+log⁡[A−][HA]\mathrm{pH}=\mathrm{p}K_a+\log\frac{[\mathrm{A^-}]}{[\mathrm{HA}]}. Titration curves show a steep section at equivalence; choose an indicator whose colour change lies within it. At half-neutralisation, pH = pKa.

    ≈ 55 min
  2. Brønsted–Lowry acids and bases

    A Brønsted–Lowry acid is a proton (H⁺) donor; a base is a proton acceptor. Every acid–base reaction has two conjugate pairs: in HCl+H2O→Cl−+H3O+\mathrm{HCl+H_2O\rightarrow Cl^-+H_3O^+}, HCl/Cl⁻ and H₃O⁺/H₂O. Strong acids dissociate fully (HCl→H++Cl−\mathrm{HCl\rightarrow H^++Cl^-}); weak acids partially (CH3COOH⇌CH3COO−+H+\mathrm{CH_3COOH\rightleftharpoons CH_3COO^-+H^+}). pH=−log⁡10[H+]\mathrm{pH}=-\log_{10}[\mathrm{H^+}]; for a strong monoprotic acid [H+]=c[\mathrm{H^+}]=c. Water is amphoteric: it can act as an acid or a base.

    ≈ 40 min