Paper 2 · Module
Differential equations
First-order equations: integrating factors
An equation can't usually be separated. Multiply through by the integrating factor : the left side becomes , exactly the derivative of a product, so one integration solves it.
≈ 40 minSecond-order equations: auxiliary equation
For , try in the "homogeneous" equation: (the auxiliary equation). Its roots give the complementary function. Add a particular integral matching , then fix the two constants with two conditions.
≈ 50 min