Gas pressure comes from molecules colliding with the walls, each collision changing momentum. Under the kinetic theory assumptions, pV=31Nm⟨c2⟩. Comparing with pV=NkT gives the mean translational kinetic energy of a molecule: 21m⟨c2⟩=23kT. Temperature is a direct measure of average molecular kinetic energy; the r.m.s. speed is ⟨c2⟩.
Cambridge 9702 Paper 4Edexcel YPH11 WPH15AQA 7408 Paper 2≈ 40 minRevision 5 · updated 2026-10-27
Section 1 of 14
Learning objectives
State the assumptions of the kinetic theory of gases.
Explain pressure in terms of molecular momentum change.
Derive and use pV=31Nm⟨c2⟩.
Use 21m⟨c2⟩=23kT and find r.m.s. speeds.
Pause and think
At the same temperature, which molecules move faster on average in air: oxygen or nitrogen?
Section 2 of 14
Core idea
Start herePressure from collisions
The air pushing on your skin is billions of molecules hitting it every nanosecond. Model them as tiny bouncing balls and Newton's laws predict the pressure, and reveal what temperature really is: average molecular kinetic energy.
The big idea
pV=31Nm⟨c2⟩. With pV=NkT: 21m⟨c2⟩=23kT.
1. Assumptions
Very many molecules, moving randomly.
Molecular volume negligible.
Elastic collisions; no forces except during collisions.
Collision time negligible.
Molecules in a box, moving randomlyEach wall collision reverses a molecule's momentum perpendicular to the wall. Billions of such impacts each second give a steady pressure.
2. Derivation
pV=31Nm⟨c2⟩
Δp=mcx−(−mcx)=2mcx
One molecule hits a wall of a cube of side L and rebounds.
Δt=cx2L
Time to return to the same wall.
F=2L/cx2mcx=Lmcx2
Rate of change of momentum.
p=L2F=Vmcx2
Pressure on that wall.
pV=Nm⟨cx2⟩
Sum over N molecules.
⟨cx2⟩=31⟨c2⟩⇒pV=31Nm⟨c2⟩
Random motion: equal in x, y, z.
31Nm⟨c2⟩=NkT⇒21m⟨c2⟩=23kT
Compare with the ideal gas equation.
Molecular speeds spread out and rise with temperatureA range of speeds at any temperature. Hotter gas: higher average speed, wider spread. cr.m.s.=m3kT.
Worked exampleNitrogen at 300 K
m=4.65×10−26 kg.
Goal
Mean KE; r.m.s. speed.
Strategy
23kT; crms=m3kT.
1
23(1.38×10−23)(300)=6.21×10−21 J
Mean KE.
2
4.65×10−263(1.38×10−23)(300)=517 m s−1
r.m.s. speed.
Answer6.21×10−21 J; 517 m s−1.
✓ CheckFaster than sound in air (sound travels via molecules) ✓.
⚠️ Common misconceptionMean speed²⟨c2⟩ is the mean of the squares, not the square of the mean.
Pause and think
300 K → 1200 K: effect on r.m.s. speed?
Summary
pV=31Nm⟨c2⟩.
⟨Ek⟩=23kT.
Key words
r.m.s. speed
Square root of the mean of squared speeds.
📜 HistoryMaxwell and Boltzmann.James Clerk Maxwell worked out the distribution of molecular speeds in 1860, and Ludwig Boltzmann extended it into statistical mechanics. Boltzmann's ideas were fiercely opposed by scientists who doubted atoms existed. His equation S=klogW is engraved on his tombstone in Vienna.
🤯 Fun factAir molecules are supersonic.At room temperature, nitrogen molecules have an r.m.s. speed of about 510 m s⁻¹, faster than the speed of sound (340 m s⁻¹). That's no coincidence: sound is carried by molecular collisions, so it can't travel faster than the molecules themselves.
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