Infrared and Mass Spectrometry
In infrared spectroscopy, bonds absorb IR at characteristic wavenumbers: O–H in alcohols (3200–3600 cm⁻¹, broad), O–H in acids (2500–3300, very broad), C=O (1680–1750, sharp, strong), N–H (3300–3500), C≡N (≈2250), C–H (2850–3100). The fingerprint region (below 1500 cm⁻¹) identifies a compound by matching. In mass spectrometry, the molecular ion (M⁺, highest significant ) gives . Fragments give structural clues (15 = CH₃⁺, 29 = C₂H₅⁺ or CHO⁺, 43 = CH₃CO⁺ or C₃H₇⁺). The M+1 peak (from ¹³C) gives the number of carbons: . M+2 peaks show Cl (3 : 1) or Br (1 : 1).
Learning objectives
- Identify functional groups from IR absorptions.
- Use the molecular ion to find .
- Interpret fragmentation peaks.
- Use M+1 and M+2 peaks.
How can an IR spectrum tell you whether an alcohol has been oxidised to an aldehyde or all the way to a carboxylic acid?
Core idea
Infrared tells you which bonds are present; a mass spectrometer tells you how heavy the molecule is and how it breaks apart.
Each bond absorbs IR at a characteristic wavenumber. The molecular ion gives ; fragments and M+1 / M+2 peaks reveal structure.
1. Infrared
Look for O–H and C=O first.
2. Mass spectrometry
- where
- n
- number of carbon atoms
- I
- peak height (abundance)
M⁺ at 72 has height 40.0; M+1 has height 1.76. How many carbons?
- Goal
- .
- Strategy
- Use the M+1 formula.
- ¹³C is 1.1% of carbon.
- Round to a whole number.
Summary
- O–H broad; C=O sharp ~1700.
- Fingerprint region: match the pattern.
- M⁺ → ; M+1 → carbons; M+2 → Cl/Br.
- Wavenumber
- Number of waves per cm (cm⁻¹).
- Molecular ion
- Ion formed by losing one electron from the whole molecule.
- Fragmentation
- Breaking of the molecular ion into smaller ions and radicals.
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