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Geometry and measures · Subtopic 9 of 17

Pyramids, Cones and Spheres

A pyramid or cone holds exactly one third of the prism with the same base and height. A sphere has volume 43πr3\tfrac43\pi r^3 and surface area 4πr24\pi r^2. Composite solids are built from these pieces: add the volumes, and count only the outside surfaces.

Cambridge 4024 Paper 1Cambridge 4024 Paper 2Edexcel 4MA1 Papers 1H, 2HEdexcel 4MA1 Papers 1F, 2FAQA 8300 Papers 1–3≈ 35 minRevision 5 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Find the volume of pyramids and cones using 13×\tfrac13\times base ×\times height.
  • Find the slant height and curved surface area of a cone.
  • Find the volume and surface area of spheres and hemispheres.
  • Work with frustums and composite solids.
Pause and think

A cone and a cylinder have the same circular base and the same height. How many cones of water would fill the cylinder?

Section 2 of 14

Core idea

Start hereThree cones fill a cylinder

Fill a cone with water and pour it into a cylinder of the same base and height. It takes exactly three cones. Pointed solids hold one-third of their matching prism.

The big idea

Pyramid/cone: V=13×base×hV=\frac13\times\text{base}\times h; cone curved surface πrl\pi rl. Sphere: V=43πr3V=\frac43\pi r^3, SA=4πr2SA=4\pi r^2.

1. The one-third rule

A cone fits inside a cylinder three times over
hrlcylinder πr²h, cone ⅓πr²h
ll (slant height), rr and hh form a right-angled triangle: l2=r2+h2l^2=r^2+h^2.
Vcone=13πr2h,curved SA=πrl,l=r2+h2V_{\text{cone}}=\tfrac13\pi r^2h,\qquad\text{curved }SA=\pi rl,\qquad l=\sqrt{r^2+h^2}
where
hh
perpendicular height.
ll
slant height.
Worked exampleCone r=3r=3, h=4h=4

Slant height, volume, total surface.

Goal
Values.
Strategy
Pythagoras for ll.
  1. l=9+16=5l=\sqrt{9+16}=5
    Right triangle r,h,lr,h,l.
  2. V=13π(9)(4)=12π=37.7V=\tfrac13\pi(9)(4)=12\pi=37.7
    Volume.
  3. π(3)(5)+π(9)=24π=75.4\pi(3)(5)+\pi(9)=24\pi=75.4
    Curved + base.
Answer55; 37.737.7 cm³; 75.475.4 cm².
✓ CheckCylinder of same size: 36π36\pi; one-third 12π12\pi ✓.

2. Spheres

Worked exampleSphere r=6r=6

Volume, surface; solid hemisphere.

Goal
Values.
Strategy
Formulas; hemisphere adds a flat circle.
  1. 43π(216)=288π=905\tfrac43\pi(216)=288\pi=905
    Volume.
  2. 4π(36)=144π=4524\pi(36)=144\pi=452
    Surface.
  3. V=144π; SA=72π+36π=108πV=144\pi;\ SA=72\pi+36\pi=108\pi
    Half, plus the flat face πr2\pi r^2.
Answer905905 cm³; 452452 cm²; hemisphere 144π144\pi, 108π108\pi.
✓ CheckHemisphere surface isn't half the sphere: it gains a circle ✓.
Worked exampleMelting and recasting

Sphere radius 6 melted into cones r=3r=3, h=4h=4.

Goal
Number of cones.
Strategy
Volume is conserved.
  1. 288π÷12π288\pi\div12\pi
    Divide volumes.
  2. =24=24
    Evaluate.
Answer2424 cones.
✓ CheckWhole number: no waste ✓.
Common misconceptionSlant vs vertical height Volume uses hh; curved surface uses ll.
Pause and think

Square pyramid base 6, height 10. Volume?

Summary

  • Pointed solids: 13\tfrac13.
  • Cone πrl\pi rl; sphere 4πr24\pi r^2.
Key words
Slant height
Apex to base edge along the surface.
HistoryArchimedes' favourite result. Archimedes proved that a sphere fits inside a cylinder with exactly 23\tfrac23 of its volume and 23\tfrac23 of its surface area. He was so proud of it that he asked for a sphere inside a cylinder to be carved on his tomb. The Roman writer Cicero reported finding the overgrown tomb about 140140 years later by that carving.
Fun factWhy bubbles are round. Of all shapes with a given volume, the sphere has the smallest surface area. Soap film pulls itself as tight as possible, so a floating bubble always becomes a sphere.
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