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Learn8300Papers 1–3 · Foundation tierAlgebraLinear and simultaneous equations
Algebra · Subtopic 3 of 9

Linear and Simultaneous Equations

An equation is a balance: whatever you do to one side, do to the other. Linear equations take a few balancing steps. Simultaneous equations have two unknowns, so you eliminate one of them first, then substitute back.

Cambridge 4024 Paper 1Cambridge 4024 Paper 2Edexcel 4MA1 Papers 1H, 2HEdexcel 4MA1 Papers 1F, 2FAQA 8300 Papers 1–3≈ 35 minRevision 6 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Solve linear equations, including with brackets, fractions and unknowns on both sides.
  • Form equations from a context and solve them.
  • Solve simultaneous linear equations by elimination or substitution.
  • Solve one linear and one quadratic equation simultaneously.
Pause and think

Two coffees and a cake cost $9\$9; one coffee and a cake cost $6\$6. How much is a coffee? You probably solved this without algebra. How?

Section 2 of 14

Core idea

Start herePens and rulers

Two pens and a ruler cost 3.20; one pen and two rulers cost 2.50. One equation with two unknowns has endless answers, but two equations together pin down exactly one pair.

The big idea

Linear equations: balance. Simultaneous: eliminate one variable by adding/subtracting, or substitute.

1. Linear equations

Worked example3(x−2)=2x+53(x-2)=2x+5

Solve.

Goal
xx.
Strategy
Expand, collect.
  1. 3x−6=2x+53x-6=2x+5
    Expand.
  2. x=11x=11
    Subtract 2x2x, add 6.
Answerx=11x=11.
✓ Check3(9)=27=22+53(9)=27=22+5 ✓.
Worked examplex+13−x−24=1\frac{x+1}3-\frac{x-2}4=1

Solve.

Goal
xx.
Strategy
Multiply everything by the LCM 12.
  1. 4(x+1)−3(x−2)=124(x+1)-3(x-2)=12
    ×12.
  2. 4x+4−3x+6=124x+4-3x+6=12
    Careful: −3×−2=+6-3\times-2=+6.
  3. x=2x=2
    Solve.
Answerx=2x=2.
✓ Check1−0=11-0=1 ✓.

2. Simultaneous equations

x + y = 7 and 2x − y = 2 cross at (3, 4)
2468−224680xyx + y = 72x − y = 2(3, 4)
The crossing point is the one pair of values that fits both equations.
Worked examplex+y=7x+y=7, 2x−y=22x-y=2

Solve.

Goal
xx, yy.
Strategy
yy coefficients are opposite: add.
  1. 3x=9⇒x=33x=9\Rightarrow x=3
    Add.
  2. y=7−3=4y=7-3=4
    Substitute.
Answerx=3x=3, y=4y=4.
✓ Check6−4=26-4=2 ✓.
Worked example3x+2y=163x+2y=16, 2x−5y=−22x-5y=-2

Solve.

Goal
xx, yy.
Strategy
Scale to match xx, subtract.
  1. 6x+4y=32,6x−15y=−66x+4y=32,\quad6x-15y=-6
    ×2 and ×3.
  2. 19y=38⇒y=219y=38\Rightarrow y=2
    Subtract.
  3. 3x+4=16⇒x=43x+4=16\Rightarrow x=4
    Substitute.
Answerx=4x=4, y=2y=2.
✓ Check8−10=−28-10=-2 ✓.
Worked examplePens and rulers

2p+r=3.202p+r=3.20, p+2r=2.50p+2r=2.50.

Goal
Prices.
Strategy
Double the second, subtract the first.
  1. 2p+4r=5.002p+4r=5.00
    ×2.
  2. 3r=1.80⇒r=0.603r=1.80\Rightarrow r=0.60
    Subtract.
  3. p=2.50−1.20=1.30p=2.50-1.20=1.30
    Substitute.
AnswerPen 1.30, ruler 0.60.
✓ Check2.60+0.60=3.202.60+0.60=3.20 ✓.
Common misconceptionSubtracting negatives (6x+4y)−(6x−15y)=4y−(−15y)=19y(6x+4y)-(6x-15y)=4y-(-15y)=19y, not −11y-11y.

Summary

  • Clear fractions by multiplying.
  • Eliminate or substitute; check in both.
Key words
Simultaneous
True at the same time.
HistoryDiophantus' age. Diophantus of Alexandria (about 250250 AD) was the first to use symbols for unknowns. A puzzle said to be his epitaph: his boyhood lasted 16\tfrac16 of his life, his beard grew after 112\tfrac1{12} more, he married after 17\tfrac17 more, his son was born 55 years later and lived half as long as his father, who died 44 years after the son. Solving the linear equation gives 8484 years.
Fun factThe Chinese elimination method. The Nine Chapters on the Mathematical Art, written in China around 200200 BC, solves simultaneous equations by arranging the numbers in a grid of counting rods and eliminating, nearly 20002000 years before Gauss gave the method his name in Europe.
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