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Work, energy and power · Subtopic 2 of 4

Kinetic and Potential Energy

Kinetic energy is the energy of motion, 12mv2\tfrac12mv^2; potential energy is the energy of height, mghmgh. With no friction or air resistance, one simply turns into the other and the total never changes.

Cambridge 9709 Paper 4Edexcel YMA01 WME02Edexcel 9FM0 OptionAQA 7367 Paper 3≈ 30 minRevision 6 · updated 2026-10-27
Section 1 of 14

Learning objectives

  • Calculate kinetic energy 12mv2\tfrac12mv^2 and changes in potential energy mghmgh.
  • Use conservation of energy when only gravity does work.
  • Solve problems on smooth curved paths, where suvat cannot be used.
  • Recognise that the speed gained depends only on the height dropped, not the mass or path.
Pause and think

Two children slide from the same height: one down a short steep slide, the other down a long twisting one. Ignoring friction, who is faster at the bottom?

Section 2 of 14

Core idea

Start hereA rollercoaster needs no engine

Once hauled to the top, a rollercoaster runs on stored energy alone. Height becomes speed, speed becomes height. Ignoring friction, the total of kinetic and potential energy never changes.

The big idea

Ek=12mv2E_k=\tfrac12mv^2; Ep=mghE_p=mgh. Without friction, Ek+EpE_k+E_p is constant.

1. Where ½mv² comes from

Work done accelerating from rest
  1. W=Fs=masW=Fs=mas
    F=maF=ma.
  2. v2=0+2as⇒as=12v2v^2=0+2as\Rightarrow as=\tfrac12v^2
    suvat from rest.
  3. W=12mv2W=\tfrac12mv^2
    Substitute: this is the kinetic energy gained.
A 2 kg ball dropped from 20 m: PE and KE as it falls
0.511.522.533.541002003004000energy (J)PE = mghKE = ½mv²total
The PE bar shrinks exactly as fast as the KE bar grows. The total stays at mgH=2(10)(20)=400mgH=2(10)(20)=400 J.
Worked example2 kg ball dropped from 20 m

Speed at the bottom, and at half way.

Goal
Speeds.
Strategy
PE lost = KE gained.
  1. mgh=2(10)(20)=400 Jmgh=2(10)(20)=400\text{ J}
    Total energy.
  2. 12(2)v2=400⇒v=20\tfrac12(2)v^2=400\Rightarrow v=20
    Bottom.
  3. 12(2)v2=200⇒v=14.1\tfrac12(2)v^2=200\Rightarrow v=14.1
    Half way: half the PE converted.
Answer2020 m/s; 14.114.1 m/s.
✓ Checksuvat: v2=2(10)(20)=400v^2=2(10)(20)=400 ✓.
Worked exampleSkier on a smooth slope

At 5 m/s, drops 15 m. Final speed?

Goal
vv.
Strategy
Energy; mass cancels.
  1. 12v2=12(25)+10(15)\tfrac12v^2=\tfrac12(25)+10(15)
    Divide through by mm.
  2. v2=325⇒v=18.0v^2=325\Rightarrow v=18.0
    Solve.
Answer18.018.0 m/s.
✓ CheckIndependent of the slope's shape ✓ (only height matters).
Pause and think

Why does mass cancel?

Summary

  • 12mv2\frac12mv^2, mghmgh.
  • Smooth: total constant.
Key words
Kinetic energy
Energy of motion.
Potential energy
Energy of position.
A 2 kg ball dropped from 10 m (g = 10 m s⁻²)
246810501001502000height h (m)energy (J)potential energy mghkinetic energytotal 200 J
Ignoring air resistance, every joule of potential energy lost becomes kinetic energy, so the total stays at mgh=2×10×10=200 Jmgh=2\times10\times10=200\text{ J}.
HistoryJoule's paddle wheel. In 1845 James Prescott Joule let a falling weight turn a paddle wheel in a tank of water, and measured the tiny rise in temperature. He showed that a fixed amount of mechanical work always produces the same amount of heat, which was the key evidence that energy is conserved, just changing form. The unit of energy is named after him.
Fun factWhy the first hill is the tallest. A roller coaster is hauled up its first hill and then runs on energy alone. Every later hill must be lower, because some energy is lost to friction and air resistance along the way. If a later hill were as tall as the first, the train would stall near the top.
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